M(s) and T(s) represent two different metals.Balance the following reaction and then determine the equilibrium constant Kfor the reaction at 25 °C.M2*(aq) + T*(ag) M(s) + T2+(aq)The standard reduction potentials are:M2 (aq) + 2e → M(s) E°(red) = -0.23 VM²+T2(aq) + 1e T (aq) E°(red) = +0.77 VRecall E (cell) = E°(cat) - E°(ano)Recall E(cell) = E°(cell) -[RT/nF] InQRecall E(cell) = E°(cell) - [(0.0592 V)/n] logQ at 25 °CR= 8.3144 Jx K-1xmol-1F-96,485 C/mal

Anode half reaction : T+ → T2+ + e- ...eq 1 Cathode half…

Balance the following reaction and then determine the equilibrium constant K for the reaction at 25°C. M2*(aq) + T*(aq) M(s) + T2*(aq) The standard reduction potentials are: M2+(ag) + 2e M(s) E°(red) = -0.23 V T2*(aq) + 1e→ T*(aq) E°(red) = +0.77 V Recall E°(cell) = E°(cat) – E°(ano) Recall E(cell) = E°(cell) - [RT/nF] InQ %3D Recall E(cell) = E°(cell) - [(0.0592 V)/n] logQ at 25 °C R= 8.3144 Jx K-1x mol-1 F = 96,485 C/mol

Balance the following reaction and then determine the equilibrium constant K for the reaction at 25°C. M2(aq) + T(aq) M(s) + T2(aq) The standard reduction potentials are: M2+(ag) + 2e M(s) E°(red) = -0.23 V T2(aq) + 1e→ T*(aq) E°(red) = +0.77 V Recall E°(cell) = E°(cat) – E°(ano) Recall E(cell) = E°(cell) - [RT/nF] InQ %3D Recall E(cell) = E°(cell) - [(0.0592 V)/n] logQ at 25 °C R= 8.3144 Jx K-1x mol-1 F = 96,485 C/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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