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Draw the corresponding position-versus-time graph for the velocity-versus-time graph shown in the figure. Assume that x=0mx=0m at t=0st=0s
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- Note : graphic in picture Question: Based on the graph above, assume Xa = 3m at time a 4 seconds, Xe = 4 m at time e 4.5 seconds, Xf = 5 m at time f 5.3 seconds and Xb = 7 m at time b 6 seconds. A. Determine the direction the particle moves, between time a and time e, time e and time f, time f and time b. B. Calculate the average velocity from time a to time e, time e to time f, time f to time b and time a to time b.a van travels a distance d=25.6m in the positive x direction in a time t1=23.7s, at which point it brakes coming to a rest in t2=8.33sa. what was the van's avergae velocity in the horizontal direction in m/s during the t1 time period?b.assuming the van started from rest and moved at a constant acceleration, what was the acceleration in m/s2 during the time interval t1?c. what was the van's instantaneous velocity in the horizontal direction in ms when it was braking?d. using the result from part c, what was the van's horizontal component of acceleration in m/s2 during the braking period?A position function is given by F(t)= (10m+20t)i-5t²j. What is the velocity of the object it describes at t=2.0s? Using the same position function as the previous problem, what is the acceleration function? Using the same position function again, make an accurate plot of the object's trajectory over the first two seconds of flight. What's the lowest speed of the object in the prior problem in that time interval? I
- A car starts from rest, then accelerates at a constant rate over a distance of 57 m. It then immediately decelerates at a constant rate over a distance of 113 m. The entire trip lasts a total duration of 27.5 s. What were the magnitudes of the car s accelerations for the speedup and slowdown stages respectively? The car comes to a complete stop at the end of the braking phase. a. 4.11 m/s^2, then 2.07 m/s^2 b. 1.34 m/s^2, then 0.68 m/s^2 c. 2.07 m/s^2, then 4.11 m/s^2 d. 0.45 m/s^2, then 0.45 m/s^2Sketch a velocity-time graph for Donna’s Mercedes which accelerated uniformly for 0 mi/hr to 70. mi/hr in 5.0 seconds. April throws a ball straight up into the air at an initial speed of 30. m/s.Q1) The position of a particle traveling along a straight line is s(t) = (t²-3t²+C) ft, where tis in seconds and C is a constant. If s = 4 ft when t= 0, determine the velocity of the particle when t =4 s. What is the total distance traveled during the time interval t = 0 to t = 4 s? Also, what is the acceleration when t = 2 s?