Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter6: Motion In Two Dimensions
Section: Chapter Questions
Problem 84A
Related questions
Question
From the above plot of velocity versus time, calculate the final position x at
t = 100 s if the initial position at t = 0 s is x0 = -25.0m? Justify your answer.
What is the object’s acceleration at t = 10 s, t = 40 s, and t = 85 s? Justify your answers.
![Kinematics in 1D: Velocity vs. Time Graphs
70
Ax =
Ax =
Ax =
Ax =
Ax = Ax%D
Ax =
Ax =
100 m
300 m
200 m
0m
0m
100 m -200m -100 m 200 m
200 m 0 m
0m
60
a= 2
Move the blue dots
a= -4
m/s
a 2
a = 0
a3D0
a = -2
a = 0
a= 2
a=D 4
a = -4
a = 0
a = 0
to adjust the velocity
m/s2
m/s
m/s
m/s
m/s²
m/s
m/s
m/s
m/s
m/s
m/s2
values on the graph.
50
40
30
Velocity (m/s)
20
10
Time (s)
10
20
30
40
60
70
80
90
100
110
120
130
140
-10
Total displacement during
time interval of
-20
shaded region 600 m
Average velocity
-30
during time interval
At = 120 s
of shaded region
=5 m/s
-40
Move the red dots to change the time interval](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6501bcec-69f0-41c7-aaf6-9d4563ecc7cd%2Fb65a8ec7-a0ac-4562-bc49-46d0558ea74d%2Ffteosl9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Kinematics in 1D: Velocity vs. Time Graphs
70
Ax =
Ax =
Ax =
Ax =
Ax = Ax%D
Ax =
Ax =
100 m
300 m
200 m
0m
0m
100 m -200m -100 m 200 m
200 m 0 m
0m
60
a= 2
Move the blue dots
a= -4
m/s
a 2
a = 0
a3D0
a = -2
a = 0
a= 2
a=D 4
a = -4
a = 0
a = 0
to adjust the velocity
m/s2
m/s
m/s
m/s
m/s²
m/s
m/s
m/s
m/s
m/s
m/s2
values on the graph.
50
40
30
Velocity (m/s)
20
10
Time (s)
10
20
30
40
60
70
80
90
100
110
120
130
140
-10
Total displacement during
time interval of
-20
shaded region 600 m
Average velocity
-30
during time interval
At = 120 s
of shaded region
=5 m/s
-40
Move the red dots to change the time interval
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