A survey and research company claims that TV network A garnered 31% audience satisfaction. To testthe claim, TV network A conducted a survey from 2000 randomly selected viewers all over the countrywith a 0.05 significance level. Which of the following is the correct null and alternative hypothesis?O a.H.: p > 0.69Ha:p = 0.69%3DO b.H.:p < 0.69Ha:p = 0.69Ос.H.: p = 0.31%3DHa:p < 0.31O d.H.:p = 0.31Ha:p > 0.31

Answered: Image /qna-images/answer/de38abf2-81d7-4cd5-a1b1-6d247f920a0d.jpg

Answered: mpany that TV network A garnered 31%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose 242 subjects are treated with a drug that is used to treat pain and 50 of them developed nausea. Use a 0.10 significance level to test the claim that more than 20% of users develop nausea. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p=0.20 H₁: p0.20 H₁: p=0.20 OC. Ho: p=0.20 H₁: p>0.20 O D. Ho: p=0.20 H₁: p=0.20
In a study of 779 randomly selected medical malpractice lawsuits, it was found that 470 of them were dropped or dismissed. Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. C Which of the following is the hypothesis test to be conducted? ⒸA. Ho: p=0.5 O B. Ho: p=0.5 H₁: p > 0.5 H₁: p=0.5 O C. Ho: p=0.5 O D. Ho: p=0.5 H₁: p 0.5 H₁: p=0.5 What is the test statistic? 2=0 (Round to two decimal places as needed.) What is the P-value? P-value= (Round to three decimal places as needed.) Next
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PLEASE ONLY SELECT THE ANSWERS AS SHOWN FOR THE MULTIPLE CHOICE, SUCH AS OPTION 1, 2, ETC. In a study of 796 randomly selected medical malpractice lawsuits, it was found that 489 of them were dropped or dismissed. Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. Which of the following is the hypothesis test to be conducted? A. H0: p>0.5 H1: p=0.5 B. H0: p<0.5 H1: p=0.5 C. H0: p≠0.5 H1: p=0.5 D. H0: p=0.5 H1: p>0.5 E. H0: p=0.5 H1: p<0.5 F. H0: p=0.5 H1: p≠0.5 What is the test statistic? Z=≠ (Round to two decimal places as needed.) What is the P-value? P-value= (Round to three decimal places as needed.) What is the conclusion about the null hypothesis? Reject the null hypothesis because the P-value is greater than the significance level, α. Reject the null hypothesis because the P-value is less than or equal to the significance level, α. Fail to reject the null hypothesis because the…
In a study of 803 randomly selected medical malpractice lawsuits, it was found that 507 of them were dropped or dismissed. Use a 0.05 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. Which of the following is the hypothesis test to be conducted? O A. Ho: p>0.5 H:p=0.5 OB. H: p=0.5 H: p#0.5 OC. Ho: p#0.5 OD. H: p=0.5 H:p=0.5 H:p0.5 H: p=0.5 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value =
a. set up appropriate null and alternative hypotheses of the test b. choose an appropriate test statistic and use the data to find the p-value
Suppose that in a random selection of 100 colored candies, 22% of them are blue. The candy company claims that the percentage of blue candies is equal to 30%. Use a 0.10 significance level to test that claim. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p=0.3 H₁: p=0.3 O B. Ho: p=0.3 H₁: p=0.3 C. Ho: p=0.3 H₁: p>0.3 O D. Ho: p=0.3 H₁: p<0.3 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. A. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 30% B. Reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 30% O C. Fail to…
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Every year during home football games the Carroll College fans do push-up contests to see how many they can do. Suppose that a curious stats student in the stands kept track of the number of push-ups completed for several students of both genders. Males 31 31 24 18 30 16 28 13 26 23 Females 16 11 10 1 26 26 6 9 16 32 Consider the hypothesis that males in this contest can do more pushups than females. Use an significance level to test the claim. The test statistic is Construct a 99% confidence interval for the mean of the differences between males and females.
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A union leader claims that absences on the different days of the week are equally likely. To test this claim, a company manager collects the data shown below. Use a 0.05 significance level to test the claim. Day Mon Tue Wed Thur Fri Absences 40 15 12 23 43 a. Before doing any calculations, do the data appear to support the union leader's claim? Why or why not? A. No, absences on The and Wed are much larger than on other days B. Yes, there are roughly the same number of absences on the different days of the week C. Yes, more absences on Mon and Fri are normal D. No, absences on Mon and Fri are much larger than on other days b. State Upper H 0 . A. At least one proportion is different than claimed B. p Subscript Mon Baseline equals 1 divided by 4 comma p Subscript Tue Baseline equals 1 divided by 4 comma p…

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