Past studies have indicated that the percentage of smokers was estimated to be about 33%. Given the newsmoking cessation programs that have been implemented, you now believe that the percentage of smokershas reduced. You randomly surveyed 2106 people and found that 656 snoke. Use a 0.05 significance level totest the claim that the percentage of smokers has reduced.a) Identify the nult and alternative hypotheses?Ho: ? vH.:? vb) What type of hypothesis test should you conduct (left-, right-, or two-tailed)?O left-tailedOright-tailedO two-tailedc) Identify the appropriate significance level.d) Calculate your test statistic. (Round your final answer to two decimal places.)e) Calculate your p-value. (Round your final answer to four decimal places.)f) Do you reject the null hypothesis?O We reject the null hypothesis, siñce the p-value is less than the significance level.O We reject the null hypothesis, since the p-value is not less than the significance level.O We do not reject the null hypothesis, since the p-value is less than the significance level.O We do not reject the null hypothesis, since the p-value is not less than the significance level.g) Select the statement below that best represents the conclusion that can be made.O There is sufficient evidence to warrant rejection of the claim that the percentage of smokers is lessthan 33%.O There is not sufficient evidence to warrant rejection of the claim that the percentage of smokers isless than 33%.O The sample data support the claim that the percentage of smokers is less than 33%.O There is not sufficient sample evidence to support the claim that the percentage of smokers is lessthan 33%

We have given that Sample size n = 2106 Favorable cases x = 656 Sample proportion p^=x/n Note:…

Answered: Past studies have indicated that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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