https:/ xP Pearso XO Chemi XO Chem x6 login. xy! usedy! nissan Xy! cargur xal?courseld316925454&OpenVellumHMAC=3ddece6bc48ff57d366ac838d66f9ee0#10001View Available Hint(s)ResetDehydrationsynthesisMonomer 1Monomer 2OH HODecompositionMonomers linked by covalent bondHydrolysisExchangeMonomer 1Monomer 2Monomers linked by covalent bondонSubmitPrevious AnswersX Incorrect; Try Again; 5 attempts remainingPearsonCopyright 2021 Pearson Education Inc. All rights reserved. | Ierms of Use Privacy PolicyI Permissions Co9988°F MosDELL

Biological macromolecules are crucial cellular components that execute a variety of functions that…

Answered: Monomer 1 Monomer 2 ОН НО- Monomers…

Monomer 1 Monomer 2 ОН НО- Monomers linked by covalent bond H,0 Monomer 1 Monomer 2 Monomers linked by covalent bond OH HO

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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I'm not sure if it's just the textbook I'm using, but how come some of the sugars' chemical structures have alternating hydroxyl and hydrogens? For example, in the depiction of galactose below, the hydroxyl group is on the "left" side twice while it is on the "right" side three times.
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Circle the functional groups on the R-group of the AMINO ACIDS below that are capable of forming hydrogen bonds. How do you know? 1 O H₂N-CH-C-O H 6 H₂N-CH-C-O CH H₂ CH₂ H₂C 2 요 H₂N-CH-C-O CH, 7 ar 3 hods word no 4hom on oq H₂N-CH-8-0-H₂N-CH-8-0 H₂N-CH-8-0- CH₂ CH₂ H₂C 201 8 CH₂ CH CH CH₂ sizoda H₂C CH₂ 10. Birds 9 H₂N-CH-8-0 H₂N-CH-8-0- CH₂ OH CH H₂C OH 578 aloriool H₂N-CH-C-O CH₂ CH₂ 0=C o 5 0=c NH₂ 요 H₂N-CH-C-O CH₂ CH₂ CH₂ CH ₂ 10 H₂N © University of California, Davis
Draw the enantiomer of the monosaccharide by changing the structure below. H ☑ H -ОН H -ОН но -H HO -H CH₂OH
F 9. In sugars that contain many chiral centers, only the chiral center that is most distant from the carbonyl carbon is designated as D (right) or L (left). Determine which of the structures below are D and L sugars. H-C-OH HIC OH H-C-OH I CH₂OH D-Ribose HO C-H H-C-OH H-C-OH I CH₂OH D-Arabinose H-C-OH HO-C-H H-C-OH H-C-OH T HO-C-H I H-C-OH I CH₂OH D-Xylose D-Aldoses Five carbons H-C-OH H-C-OH HO-C-H H-C-OH HO-C-H HO-C-H H-C-OH CH₂OH CH₂OH CH₂OH CH₂OH D-Ribose D-Arabinose D-Xylose D-Lyxose HO-C-H HO-C-H H- H-C-OH CHO IMPORTANT NOTE: most hexoses in living organism are D isomers. Thus, the D prefix is often omitted. DO NOT confuse this with amino acids. Remember that the most common amino acids in living organism are L isomers. L sugars are mirror images of D sugars. H-C-OH -OH 10. Sugars (monosaccharides) can be trioses, tetroses, pentoses, hexoses, heptoses, etc., depending on the number of carbons they have. Determine the number of carbons in the structures above (#9) and determine…
Indicate next to each letter the name of the monomers shown below and write the name of the polymer that is produced from the monomer. H-C-OH HỌ-C-H H-C-OH H-C-OH о- 6 CH₂OH 0=P-O О CH₂ Phosphate H group А: Name of polymer: H- Н Н OH H Sugar Н Н. H Nitrogenous base (adenine) C: 0 НО Name of polymer: H C-C-N CH2 SH Н НИ Н III H-N-С-С-0 +111 НКН н B: Name of polymer: Н 0 0-C-H o Н-С-0² H-C-O H S ННННННННННН Н Н Н LI -CH Н ННННННННННН Н Н Н ITIILE I C-C H ...... С-с-с-с-с-с-с III E .. ННННННННННН Н Н С-С-f 111 1 FE D: I НННННННННННННН No polymer!
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10 12 3 13 4 9 10 8 14 What is the structure labeled "6" in the image?