Mixture of NH,CI, NaCl, SiO, Iron Shavings First Separation Technique First Separated Component Remaining Components Second Separation Technique Second Separated Component Remaining Components Third Separati on Technique Third Separated Remaining Component Component

Mixture of NH,CI, NaCl, SiO, Iron Shavings First Separation Technique First Separated Component Remaining Components Second Separation Technique Second Separated Component Remaining Components Third Separati on Technique Third Separated Remaining Component Component

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Mixture of NH.CI, NaCl, SiO,, Iron Shavings
First Separation
Technique
First Separated
Component
Remaining Components
Second Separation
Technique
Second Separated
Component
Remaining Components
Third Separation
Technique
Third Separated
Remaining Component
Component

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ASSAY Calibration solutions Calibration solutions of naproxen in the range 5 – 25 μg/mL were prepared. Sample preparation 20 tablets weighing 12.3819 g were crushed to a fine powder. A portion of the powder (145.4 mg) was shaken with approximately 150 mL of acetic acid (0.05 M) for 5 min and then made up to volume in a 250 mL volumetric flask (stock solution). Approximately 50 mL of the stock solution was filtered and a 25 mL aliquot was diluted to 100 mL in a volumetric flask. 10 mL of the resulting solution was further diluted to 100 mL with acetic acid (0.05 M). Analysis The standards and sample solutions were analyzed by HPLC under the following conditions: Column: octadecylsilyl (ODS), 4.6 mmx150 mm, mobile phase: acetonitrile : 0.05 M acetic acid (85:15), flow rate: 1 ml/min, UV detection at 243 nm. Results: A calibration curve of concentration versus peak area was constructed for the standard solutions and gave the straight-line equation: y = 3555.6x + 85, r = 0.9999 The area…