Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Need help to calculate for percentage % recovery
![### Experimental Data and Calculations for Methyl Benzoate
#### Materials Used:
- **Methyl benzoate:** 1.00 mL
- **H₂SO₄ (Sulfuric Acid):** 1.00 mL
- **HNO₃ (Nitric Acid):** 1.20 mL
#### Product Information:
- **Crude product:** 0.99 g
- **Pure product:** 0.45 g
#### Melting Points:
- **Observed melting point:** 55° - 63°C
- **Expected melting point:** 78° - 80°C
#### Additional Properties:
- **Density of methyl benzoate:** 1.094 g/mL
- **Molar mass of product:** 136.15 g/mol
#### Calculations:
1. **Limiting Agent:**
- **Methyl Benzoate** is the limiting reagent.
2. **Density and Mass:**
- Density of methyl benzoate = 1.094 g/mL
- Mass of methyl benzoate used:
\[
\text{Mass} = \text{Volume} \times \text{Density} = 1.00\, \text{mL} \times 1.08\, \text{g/mL} = 1.094\, \text{g}
\]
3. **Theoretical Yield Calculation:**
- Formula:
\[
\text{Theoretical Yield} = \left( \frac{\text{Mass of methyl benzoate}}{\text{Molar mass of methyl benzoate}} \right) \times \text{Molecular mass of product}
\]
- Substituting values:
\[
= \left( \frac{1.094\, \text{g}}{136.15\, \text{g/mol}} \right) \times 181.1\, \text{g/mol} = 1.45\, \text{g}
\]
4. **Percentage Yield:**
- Formula:
\[
\text{Percentage Yield} = \left( \frac{\text{Actual yield}}{\text{Theoretical yield}} \right) \times 100
\]
- Substituting values:
\[
= \left( \frac{0.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F46abcb61-b74c-47ad-92fe-fd35f6687cc0%2F1366f82f-ec96-4238-8204-47ffe9184a00%2Fx2sy344_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Experimental Data and Calculations for Methyl Benzoate
#### Materials Used:
- **Methyl benzoate:** 1.00 mL
- **H₂SO₄ (Sulfuric Acid):** 1.00 mL
- **HNO₃ (Nitric Acid):** 1.20 mL
#### Product Information:
- **Crude product:** 0.99 g
- **Pure product:** 0.45 g
#### Melting Points:
- **Observed melting point:** 55° - 63°C
- **Expected melting point:** 78° - 80°C
#### Additional Properties:
- **Density of methyl benzoate:** 1.094 g/mL
- **Molar mass of product:** 136.15 g/mol
#### Calculations:
1. **Limiting Agent:**
- **Methyl Benzoate** is the limiting reagent.
2. **Density and Mass:**
- Density of methyl benzoate = 1.094 g/mL
- Mass of methyl benzoate used:
\[
\text{Mass} = \text{Volume} \times \text{Density} = 1.00\, \text{mL} \times 1.08\, \text{g/mL} = 1.094\, \text{g}
\]
3. **Theoretical Yield Calculation:**
- Formula:
\[
\text{Theoretical Yield} = \left( \frac{\text{Mass of methyl benzoate}}{\text{Molar mass of methyl benzoate}} \right) \times \text{Molecular mass of product}
\]
- Substituting values:
\[
= \left( \frac{1.094\, \text{g}}{136.15\, \text{g/mol}} \right) \times 181.1\, \text{g/mol} = 1.45\, \text{g}
\]
4. **Percentage Yield:**
- Formula:
\[
\text{Percentage Yield} = \left( \frac{\text{Actual yield}}{\text{Theoretical yield}} \right) \times 100
\]
- Substituting values:
\[
= \left( \frac{0.
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