min -5x1 –- x2 + 12x3 subject to 3x1 + 2x2 + x3 = 10 5x1 + 3x2 + +x4 16 X; > 0, i = 1, 2, 3, 4. for which we already have an optimal solution in the following tableau: X1 X2 X3 X4 12 2 7 2 1 -3 x2 = 1 -3
min -5x1 –- x2 + 12x3 subject to 3x1 + 2x2 + x3 = 10 5x1 + 3x2 + +x4 16 X; > 0, i = 1, 2, 3, 4. for which we already have an optimal solution in the following tableau: X1 X2 X3 X4 12 2 7 2 1 -3 x2 = 1 -3
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Consider the following standard form LP problem (attached image):
Let us introduce the additional constraint x1 + x2 = 3. Form the auxiliary problem and solve it using the big-M method.
![min -5x1 –- x2 + 12x3
subject to
3x1 + 2x2 + x3
= 10
5x1 + 3x2 +
+x4
16
X; > 0, i = 1, 2, 3, 4.
for which we already have an optimal solution in the following tableau:
X1
X2
X3
X4
12
2
7
2
1
-3
X2 =
1
-3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F138bcebf-db0b-42f0-bb5c-dfa12c40df11%2F32a9ce25-ae36-4489-91ce-1c28c2ddef3a%2Fd0mdifm_processed.png&w=3840&q=75)
Transcribed Image Text:min -5x1 –- x2 + 12x3
subject to
3x1 + 2x2 + x3
= 10
5x1 + 3x2 +
+x4
16
X; > 0, i = 1, 2, 3, 4.
for which we already have an optimal solution in the following tableau:
X1
X2
X3
X4
12
2
7
2
1
-3
X2 =
1
-3
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