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1. Max z = 2x, + X,+ 2x3 Subject to 4x + 3x2 + 8xs 12 4x, + X+ 12x,s 8 4x- X2+ 3x5 8 X1, X2, Xg 20 2. min z = 2x+ X2 subject to 3x;+ X = 3* 4x+ 3x, 26 X+ 2x2 s3 X1, X2 20

1. Max z = 2x, + X,+ 2x3 Subject to 4x + 3x2 + 8xs 12 4x, + X+ 12x,s 8 4x- X2+ 3x5 8 X1, X2, Xg 20 2. min z = 2x+ X2 subject to 3x;+ X = 3* 4x+ 3x, 26 X+ 2x2 s3 X1, X2 20

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve the following LP using the simplex method:

 

Note: The constraint with the "=" sign in the simplex iteration is added with an artificial variable, so that it becomes 3x1 + x2 + A1= 3

1. Max z = 2x, + X,+ 2x3 Subject to 4x1+ 3x2 + 8x) s 12 4x, + X+ 12x,58 4x- X2+ 3x5 8 X1, X2, Xg 20 2. min z= 2x+ x2 subject to 3x;+ X = 3* 4x+ 3x, 2 6 X+ 2x2 53 X1, X2 20
Transcribed Image Text:1. Max z = 2x, + X,+ 2x3 Subject to 4x1+ 3x2 + 8x) s 12 4x, + X+ 12x,58 4x- X2+ 3x5 8 X1, X2, Xg 20 2. min z= 2x+ x2 subject to 3x;+ X = 3* 4x+ 3x, 2 6 X+ 2x2 53 X1, X2 20
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