*3-41. Consider the problem Маximize z %3D х, + 5х, + Зx; subject to X1 + 2x2 + x3 = 6 2x1 - x2 = 8 X1, X2, X3 2 () The variable x3 plays the role of a slack. Thus, no artificial variable is needed in the first constraint. In the second constraint, an artificial variable, R, is needed. Solve the problem using x3 and R as the starting variables.

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Chapter2: Second-order Linear Odes
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Consider the problem
Maximize z = x1 + 5x2 + 3x3
subject to
x1 + 2x2 + x3 = 6
2x1 - x2 = 8
x1, x2, x3 >= 0
The variable x3 plays the role of a slack. Thus, no artificial variable is needed in the first
constraint. In the second constraint, an artificial variable, R, is needed. Solve the problem
using x3 and R as the starting variables.

*3-41. Consider the problem
Maximize z = x1 + 5x2 + 3x3
subject to
X1 + 2x2 + x3 = 6
2x1
X2
= 8
X1, X2, X3 2 ()
The variable xz plays the role of a slack. Thus, no artificial variable is needed in the first
constraint. In the second constraint, an artificial variable, R, is needed. Solve the problem
using x3 and R as the starting variables.
Transcribed Image Text:*3-41. Consider the problem Maximize z = x1 + 5x2 + 3x3 subject to X1 + 2x2 + x3 = 6 2x1 X2 = 8 X1, X2, X3 2 () The variable xz plays the role of a slack. Thus, no artificial variable is needed in the first constraint. In the second constraint, an artificial variable, R, is needed. Solve the problem using x3 and R as the starting variables.
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