Question 29 Maximize 2x1 + 4x2 subject to 1 + 3x2 12 2x1 + x₂ 14 120 and ₂ ≥ 0 Using simplex method by introducing slack variables 3 and 4, and M = 2x1 + 4x2, now the inequalities are changed to equations x₁ + 3x2 + x3 = 12 (1) 2x1 + x2 + x4 = 14 (2) 2x1 + 4x2 M = 0 (3) To bring 1 and 2 into the solution, which one (1 or 2) is firstly brought into the solution and which equation is used as the pivot equatio O1 and (2) O2 and (3) O #2 and (2) O1 and (1) O2 and (1)
Question 29 Maximize 2x1 + 4x2 subject to 1 + 3x2 12 2x1 + x₂ 14 120 and ₂ ≥ 0 Using simplex method by introducing slack variables 3 and 4, and M = 2x1 + 4x2, now the inequalities are changed to equations x₁ + 3x2 + x3 = 12 (1) 2x1 + x2 + x4 = 14 (2) 2x1 + 4x2 M = 0 (3) To bring 1 and 2 into the solution, which one (1 or 2) is firstly brought into the solution and which equation is used as the pivot equatio O1 and (2) O2 and (3) O #2 and (2) O1 and (1) O2 and (1)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Question 29
Maximize 2x1 + 4x2
subject to
x1 + 3x₂ ��� 12
2x1 + x₂ ≤ 14
120 and ₂ > 0
Using simplex method by introducing slack variables 3 and 4, and M = 2x1 + 4x2, now the inequalities are changed to equations
x1 + 3x2 + x3 = 12
(1)
2x1 + x₂ + x4 = 14
(2)
2x14x2 M = 0
(3)
To bring 1 and 2 into the solution, which one (1 or 2) is firstly brought into the solution and which equation is used as the pivot equation.
O1 and (2)
O #2 and (3)
O2 and (2)
O #1 and (1)
O2 and (1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa908b33b-3c65-4b95-8292-a806755b1d52%2Fee7becda-c879-4310-ae2c-fa64c9ac92af%2Fw8w3tk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 29
Maximize 2x1 + 4x2
subject to
x1 + 3x₂ ��� 12
2x1 + x₂ ≤ 14
120 and ₂ > 0
Using simplex method by introducing slack variables 3 and 4, and M = 2x1 + 4x2, now the inequalities are changed to equations
x1 + 3x2 + x3 = 12
(1)
2x1 + x₂ + x4 = 14
(2)
2x14x2 M = 0
(3)
To bring 1 and 2 into the solution, which one (1 or 2) is firstly brought into the solution and which equation is used as the pivot equation.
O1 and (2)
O #2 and (3)
O2 and (2)
O #1 and (1)
O2 and (1)
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