METALS T01/S03 The density of K is 862 cell is a whole number. kg/m3 and the cell volume is 1.51 x 10-22 mL. Determine the number of atoms in the unit cell. Note: the number of atoms in a unit Molar Mass (g/mol) K 39.098 Packing bcc body centered cubic ccp cubic close pack hcp hexagonal close pack Avogadro's No. (mol"1) 6.022x1023

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Can you please answer this with serious detail and depth, as in every last little step explained as tho i were a 3rd grader because i am using this to cram study I havent paid attention all quarter!!

METALS T01/S03
The density of K is 862
cell is a whole number.
kg/m3 and the cell volume
is 1.51
x 10-22 mL. Determine the number of atoms in the unit cell. Note: the number of atoms in
a unit
Molar Mass (g/mol)
K 39.098
Packing
bcc body centered cubic
ccp cubic close pack
hcp hexagonal close pack
Avogadro's No. (mol"1)
6.022x1023
Transcribed Image Text:METALS T01/S03 The density of K is 862 cell is a whole number. kg/m3 and the cell volume is 1.51 x 10-22 mL. Determine the number of atoms in the unit cell. Note: the number of atoms in a unit Molar Mass (g/mol) K 39.098 Packing bcc body centered cubic ccp cubic close pack hcp hexagonal close pack Avogadro's No. (mol"1) 6.022x1023
Expert Solution
Step 1

The number of atoms per unit cell, Z, is calculated as shown below where V is the volume of the unit cell, NA is the Avogadro’s number, d is the density of the unit cell, and M is the molar mass of the potassium.

Chemistry homework question answer, step 1, image 1
Step 2

The conversion for mL to m3 is shown below. Thus, 1.51×10-22 mL equal to 1.51×10-28 m3.

Chemistry homework question answer, step 2, image 1
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