. calculator6 Families vs 1 Fake Family | Odd Man...My HomeOWLV2 | Online teaching and learning..Details[Review Topics](References]Use the References to access important values if needed for this question.In a study of the gas phase decomposition of dinitrogen pentoxide at 335 KN2O5(g)2 NO,(g) + ½ O2(g)the concentration of N,Og was followed as a function of time.It was found that a graph of In[N,O5] versus time in seconds gave a straight line with a slope of -6.77×10³ s and a y-intercept of -2.17 .Based on this plot, the reaction isO order in N,0g and the half life for the reaction isseconds.Submit AnswerRetry Entire Group9 more group attempts remainingPreviousNex [Review Topics][References]Use the References to access important values if needed for this question.In a study of the decomposition of ammonia on a tungsten surface at 1100 °CNH31/2 N2 + 3/2 H2the concentration of NH3 was followed as a function of time.It was found that a graph of [NH3] versus time in seconds gave a straight line with a slope of -4.49x10-6 M s and a y-intercept of 1.41x10-² M.Based on this plot, the reaction isorder in NH3 and the rate constant for the reaction isMs!.Submit AnswerRetry Entire Group9 more group attempts remainingPreviousNext

According to our policy, experts allowed to answer one question at a time. Answer to the first problem is given below. you can upload another question again. Thanks Answer 1: The reaction is First ORDER and the half-life of the reaction is 102.36 s For a first-order reaction, Reactant --> Product [R]i = initial concentration of Reactant [R]f = final concentration of Reactant k is rate constant, and t is time Integrated rate equation is ln[R]f = ln[R]i - k . t For a first-order reaction, on plotting ln[R] vs time (t), we get a straight line with a negative slope (-k). hence, the value for the rate constant in the given problem is 6.77 x 10-3 s-1 The expression for the half life (t1/2) = 0.693k=0.6930.00677s-1=102.36 s

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In a study of the gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g)2 NO2(g) + ½ O2(g) the concentration of N,Os was followed as a function of time. It was found that a graph of In[N,O5] versus time in seconds gave a straight line with a slope of-6.77×10s and a y-intercept of -2.17 Based on this plot, the reaction is O order in N,0g and the half life for the reaction is seconds.

In a study of the gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g)2 NO2(g) + ½ O2(g) the concentration of N,Os was followed as a function of time. It was found that a graph of In[N,O5] versus time in seconds gave a straight line with a slope of-6.77×10s and a y-intercept of -2.17 Based on this plot, the reaction is O order in N,0g and the half life for the reaction is seconds.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Chemical Reactions and Equations

When a chemical species is transformed into another chemical species it is said to have undergone a chemical reaction. It consists of breaking existing bonds and forming new bonds by changing the position of electrons. These reactions are best explained using a chemical equation.

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6 Families vs 1 Fake Family | Odd Man...
My Home
OWLV2 | Online teaching and learning..
Details
[Review Topics]
(References]
Use the References to access important values if needed for this question.
In a study of the gas phase decomposition of dinitrogen pentoxide at 335 K
N2O5(g)2 NO,(g) + ½ O2(g)
the concentration of N,Og was followed as a function of time.
It was found that a graph of In[N,O5] versus time in seconds gave a straight line with a slope of -6.77×10³ s and a y-intercept of -2.17 .
Based on this plot, the reaction is
O order in N,0g and the half life for the reaction is
seconds.
Submit Answer
Retry Entire Group
9 more group attempts remaining
Previous
Nex

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