4. 1 NaCI + 1 AgNO, → 1 AgCl + 1 NANO3 (a) 78.00 g of NaCl should produce how many grams of AgCl? (b) How many grams of AgCl can be produced from 107.0 g of AGNO,?

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Clusswork for 2021 6lh Period X
E Danesha Pattersc
ocs.google.com/document/d/1LEZRFXXFdGngaq0RJV4M5-0mro0UZhobATQb6eyS451/edit
rson - 2/2 Tues. Worksheet #3- Grams to Grams Practice O
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Comic San..
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BIUA
2. I 3
4.
1 NaCI + 1 AgNO3 → 1 AgCl
+ 1 NANO3
(a) 78.00 g of NaCl should produce how many grams of AgCl?
(b) How many grams of AgCl can be produced from 107.0 g of AGNO,?
Transcribed Image Text:Clusswork for 2021 6lh Period X E Danesha Pattersc ocs.google.com/document/d/1LEZRFXXFdGngaq0RJV4M5-0mro0UZhobATQb6eyS451/edit rson - 2/2 Tues. Worksheet #3- Grams to Grams Practice O Insert Format Tools Add-ons Help Last edit was 8 days ago 00% |Normal text Comic San.. 12 BIUA 2. I 3 4. 1 NaCI + 1 AgNO3 → 1 AgCl + 1 NANO3 (a) 78.00 g of NaCl should produce how many grams of AgCl? (b) How many grams of AgCl can be produced from 107.0 g of AGNO,?
Expert Solution
Step 1

1) Because stochiometry of all reactant and product is one that means the no of moles used if both reactant is 1each and no of moles produced of both product will be one for each product.

Molar mass of NaCl is 58.5 g/mol

Given mass of NaCl is 78 g

No. Of moles= Given mass/Molar mass

=78/58.5 = 1.33 moles

Which is equal to no. Of moles produced of AgCl

No. Of moles= produced mass/Molar mass 

1.33 = Mass/143.5

Mass produced= 191.3 g

 

 

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