Medicare spending per patient in different U.S. metropolitan areas may differ. Based on the sample data below, answer the questions that follow to determine whether the average spending in the northern region is significantly less than the average spending in the southern region at the 1 percent level. 1) Specify decision rule. Reject the null hypothesis if tcalc <____ 2) Find the test statistic tcalc assuming unequal variances Medicare Spending per Patient (adjusted for age, sex, and race) Statistic Northern Region Southern Region Sample mean $4324 $7,426 Sample standard deviation $1,537 $3,495 Sample size 11 patients 18 patients
Medicare spending per patient in different U.S. metropolitan areas may differ. Based on the sample data below, answer the questions that follow to determine whether the average spending in the northern region is significantly less than the average spending in the southern region at the 1 percent level. 1) Specify decision rule. Reject the null hypothesis if tcalc <____ 2) Find the test statistic tcalc assuming unequal variances Medicare Spending per Patient (adjusted for age, sex, and race) Statistic Northern Region Southern Region Sample mean $4324 $7,426 Sample standard deviation $1,537 $3,495 Sample size 11 patients 18 patients
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Medicare spending per patient in different U.S. metropolitan areas may differ. Based on the sample data below, answer the questions that follow to determine whether the average spending in the northern region is significantly less than the average spending in the southern region at the 1 percent level. 1) Specify decision rule. Reject the null hypothesis if tcalc <____ 2) Find the test statistic tcalc assuming unequal variances |
Medicare Spending per Patient (adjusted for age, sex, and race) | ||
Statistic | Northern Region | Southern Region |
Sample mean | $4324 | $7,426 |
Sample standard deviation | $1,537 | $3,495 |
|
11 patients |
18 patients |
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