Can the duration of musicians’ performance be explained by the type of music they play? The data for a hypothetical One Way ANOVA is shown below, along with the summary data and a boxplot. a. Please state H0 and H1

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Author:Amos Gilat
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Can the duration of musicians’ performance be explained by the type of music they play? The data for a hypothetical One Way ANOVA is shown below, along with the summary data and a boxplot.

a. Please state H0 and H1

b. Is the Tukey post hoc test called for? Justify. Note that you are asked, as part of your answer, to report both variance estimates and the test statistic, which have been left blank; please show your work for these.

c. A portion of the q table is given below. If Tukey is called for, use the q table to report the HSD.

d. If Tukey is called for, please perform it on the answer sheet.

e. If Tukey is called for, please identify the clusters.

Rock Bluegrass
35
Classical
SUMMARY
droups
Folk
Sure
Averoge Volance
227 37.83333 930007
Count
60
36
62
ROck
Blueeras
Folk
35
62
39
67
393
18.7
2440.6666711 B6667
68.5
40
36
38
65
68
Classical
16:
411
13.9
65
40
71
41
70
43:
71
42
71
46
72
ANOVA
Alpha = 0.05
crit
831E 13 3.0098391
!!
S5
df
Source of Variotion
Between Groups
Within Groups
MS
4671.458
269.1667
20
12969 26376-32197.82 119 45 397 42.357
Total
4940.625
23
S0 S 750 LA 7
1089T OLES FEO FEE SEE
Duration
S SIE 109 S 767
244 5432
23
21 3.326 EZ6
24- 2919
a2911 352 E
Transcribed Image Text:Rock Bluegrass 35 Classical SUMMARY droups Folk Sure Averoge Volance 227 37.83333 930007 Count 60 36 62 ROck Blueeras Folk 35 62 39 67 393 18.7 2440.6666711 B6667 68.5 40 36 38 65 68 Classical 16: 411 13.9 65 40 71 41 70 43: 71 42 71 46 72 ANOVA Alpha = 0.05 crit 831E 13 3.0098391 !! S5 df Source of Variotion Between Groups Within Groups MS 4671.458 269.1667 20 12969 26376-32197.82 119 45 397 42.357 Total 4940.625 23 S0 S 750 LA 7 1089T OLES FEO FEE SEE Duration S SIE 109 S 767 244 5432 23 21 3.326 EZ6 24- 2919 a2911 352 E
Expert Solution
Part a

The hypothesis being tested is:

H0: µ1 = µ2 = µ3 = µ4

Ha: At least one means is not equal

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