Where are the deer? Random samples of square-kilometer plots were taken in different ecological locations of a national park. The deer counts per square kilometer were recorded and are shown in the following table. Mountain Brush Sagebrush Grassland Pinon Juniper 30 20 5 25 59 10 25 16 2 24 19 4 Shall we reject or accept the claim that there is no difference in the mean number of deer per square kilometer in these different ecological locations? Use a 5% level of significance. (a) What is the level of significance? State the null and alternate hypotheses. Ho: ?1 = ?2 = ?3; H1: Exactly two means are equal.Ho: ?1 = ?2 = ?3; H1: At least two means are equal.    Ho: ?1 = ?2 = ?3; H1: All three means are different.Ho: ?1 = ?2 = ?3; H1: Not all the means are equal. (b) Find SSTOT, SSBET, and SSW and check that SSTOT = SSBET + SSW. (Use 3 decimal places.) SSTOT =   SSBET =   SSW =   Find d.f.BET, d.f.W, MSBET, and MSW. (Use 2 decimal places for MSBET, and MSW.) dfBET =   dfW =   MSBET =   MSW =   Find the value of the sample F statistic. (Use 3 decimal places.) What are the degrees of freedom?  (numerator)  (denominator) (c) Find the P-value of the sample test statistic. P-value > 0.1000.050 < P-value < 0.100    0.025 < P-value < 0.0500.010 < P-value < 0.0250.001 < P-value < 0.010P-value < 0.001

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Where are the deer? Random samples of square-kilometer plots were taken in different ecological locations of a national park. The deer counts per square kilometer were recorded and are shown in the following table.

Mountain Brush Sagebrush Grassland Pinon Juniper
30 20 5
25 59 10
25 16 2
24 19 4

Shall we reject or accept the claim that there is no difference in the mean number of deer per square kilometer in these different ecological locations? Use a 5% level of significance.

(a) What is the level of significance?


State the null and alternate hypotheses.
Ho: ?1 = ?2 = ?3H1: Exactly two means are equal.Ho: ?1 = ?2 = ?3H1: At least two means are equal.    Ho: ?1 = ?2 = ?3H1: All three means are different.Ho: ?1 = ?2 = ?3H1: Not all the means are equal.

(b) Find SSTOT, SSBET, and SSW and check that SSTOT = SSBET + SSW. (Use 3 decimal places.)
SSTOT =  
SSBET =  
SSW =  

Find d.f.BET, d.f.W, MSBET, and MSW. (Use 2 decimal places for MSBET, and MSW.)
dfBET =  
dfW =  
MSBET =  
MSW =  

Find the value of the sample F statistic. (Use 3 decimal places.)


What are the degrees of freedom?
 (numerator)
 (denominator)

(c) Find the P-value of the sample test statistic.
P-value > 0.1000.050 < P-value < 0.100    0.025 < P-value < 0.0500.010 < P-value < 0.0250.001 < P-value < 0.010P-value < 0.001

(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis?
Since the P-value is greater than the level of significance at ? = 0.05, we do not reject H0.Since the P-value is less than or equal to the level of significance at ? = 0.05, we reject H0.    Since the P-value is greater than the level of significance at ? = 0.05, we reject H0.Since the P-value is less than or equal to the level of significance at ? = 0.05, we do not reject H0.

(e) Interpret your conclusion in the context of the application.
At the 5% level of significance there is insufficient evidence to conclude that the means are not all equal.At the 5% level of significance there is sufficient evidence to conclude that the means are not all equal.    At the 5% level of significance there is insufficient evidence to conclude that the means are all equal.At the 5% level of significance there is sufficient evidence to conclude that the means are all equal.

(f) Make a summary table for your ANOVA test.
Source of
Variation
Sum of
Squares
Degrees of
Freedom
MS F
Ratio
P Value Test
Decision
Between groups          ---Select--- p-value > 0.100 0.050 < p-value < 0.100 0.025 < p-value < 0.050 0.010 < p-value < 0.025 0.001 < p-value < 0.010 p-value < 0.001  ---Select--- Do not reject H0. Reject H0.
Within groups            
Total          
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