me beam shown ists of a 200 GPa; /= 1120 × 106 mm4]. If w= 66 kN/m and P= 128 kN, determine: AY, V P A 1.5 m B W 3.5 m Tal Steel C numerator EI e-mange shape [2 2.5 m Figure Q.2 Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore, the released beam is simply supported between A and D. a) Calculate the value of the deflection at point B due to uniformly distributed load win the form D UB Note: E/will cancel out in further calculations. Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the positive direction of deflection in the positive direction of v axis. X
me beam shown ists of a 200 GPa; /= 1120 × 106 mm4]. If w= 66 kN/m and P= 128 kN, determine: AY, V P A 1.5 m B W 3.5 m Tal Steel C numerator EI e-mange shape [2 2.5 m Figure Q.2 Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore, the released beam is simply supported between A and D. a) Calculate the value of the deflection at point B due to uniformly distributed load win the form D UB Note: E/will cancel out in further calculations. Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the positive direction of deflection in the positive direction of v axis. X
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Please do following
![a * 14
200 GPa; /= 1120 × 106 mm4]. If w=66 kN/m and P= 128 kN, determine:
P
AY, V
A
1.5 m
B
W
3.5 m
leet
[VIT
C
numerator
ΕΙ
de-itange snape [E
2.5 m
Figure Q.2
Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore,
the released beam is simply supported between A and D.
a) Calculate the value of the deflection at point B due to uniformly distributed load win the
form
D
UB
Note: E/ will cancel out in further calculations.
Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the
positive direction of deflection in the positive direction of v axis.
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F97169250-b02b-4db2-9610-24afc15ffb22%2F71b9b0af-7e21-4be0-8e63-5011b9a443e6%2Ftpb7516_processed.jpeg&w=3840&q=75)
Transcribed Image Text:a * 14
200 GPa; /= 1120 × 106 mm4]. If w=66 kN/m and P= 128 kN, determine:
P
AY, V
A
1.5 m
B
W
3.5 m
leet
[VIT
C
numerator
ΕΙ
de-itange snape [E
2.5 m
Figure Q.2
Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore,
the released beam is simply supported between A and D.
a) Calculate the value of the deflection at point B due to uniformly distributed load win the
form
D
UB
Note: E/ will cancel out in further calculations.
Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the
positive direction of deflection in the positive direction of v axis.
X
Transcribed Image Text:e) Calculate the vertical reaction at support A. Enter your answer in kN to two decimal places.
Answer:
Check
Part B. The magnitude of the maximum bending stress in the beam.
f) Find the maximum bending moment in the beam. Enter your answer in kNm to two decimal
places.
Expert Solution
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Step 1: Introducing given data
VIEWStep 2: Taking reaction at B as redundant
VIEWStep 3: Calculate vertical reaction at A for simply supported beam AD for udl & load
VIEWStep 4: Using double integration method to calculate deflection at B due to udl w
VIEWStep 5: Using double integration method to calculate deflection at B due to load P
VIEWStep 6: Using double integration method to calculate deflection at B due to reaction By
VIEWStep 7: Calculate reaction at B
VIEWStep 8: Calculation of maximum bending moment
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