Match the function with the graph. A) g(x) = (x-4)² -10 B) g(x) = x² + 4 10 x C) g(x)=x²-4 D) g(x) = (x + 4)²

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter1: Expressions And Functions
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### Match the Function with the Graph

Below is a task to match the function with its corresponding graph based on the given options.

#### Functions:

A) \( g(x) = \frac{1}{3}(x - 4)^2 \)

B) \( g(x) = \frac{1}{3}x^2 + 4 \)

C) \( g(x) = \frac{1}{3}x^2 - 4 \)

D) \( g(x) = (x + 4)^2 \)

#### Graph Explanation:

In the middle of the image is a coordinate plane with the x-axis and y-axis ranging from -10 to 10. There is one parabola graphed which opens upwards and has a vertex at the point (0, -4).

#### Visual Analysis of the Graph:
1. **Vertex Identification**: The vertex of the parabola appears to be on the y-axis at (0, -4).
2. **Opening Direction**: The parabola opens upwards, indicating a positive leading coefficient.

Given this information:

- Option A \(\left( g(x) = \frac{1}{3}(x - 4)^2 \right)\) shifts the graph to the right.
- Option B \(\left( g(x) = \frac{1}{3}x^2 + 4 \right)\) shifts the graph upwards.
- Option D \(\left( g(x) = (x + 4)^2 \right)\) shifts the graph to the left.
- Option C \(\left( g(x) = \frac{1}{3}x^2 - 4 \right)\) shifts the graph downwards by 4 units.

Considering the graph provided, the correct function that matches the graph is:

**C) \( g(x) = \frac{1}{3}x^2 - 4 \)**

The graph shows a parabola opening upwards with a vertex at (0, -4), which corresponds to the function \( g(x) = \frac{1}{3}x^2 - 4 \).
Transcribed Image Text:### Match the Function with the Graph Below is a task to match the function with its corresponding graph based on the given options. #### Functions: A) \( g(x) = \frac{1}{3}(x - 4)^2 \) B) \( g(x) = \frac{1}{3}x^2 + 4 \) C) \( g(x) = \frac{1}{3}x^2 - 4 \) D) \( g(x) = (x + 4)^2 \) #### Graph Explanation: In the middle of the image is a coordinate plane with the x-axis and y-axis ranging from -10 to 10. There is one parabola graphed which opens upwards and has a vertex at the point (0, -4). #### Visual Analysis of the Graph: 1. **Vertex Identification**: The vertex of the parabola appears to be on the y-axis at (0, -4). 2. **Opening Direction**: The parabola opens upwards, indicating a positive leading coefficient. Given this information: - Option A \(\left( g(x) = \frac{1}{3}(x - 4)^2 \right)\) shifts the graph to the right. - Option B \(\left( g(x) = \frac{1}{3}x^2 + 4 \right)\) shifts the graph upwards. - Option D \(\left( g(x) = (x + 4)^2 \right)\) shifts the graph to the left. - Option C \(\left( g(x) = \frac{1}{3}x^2 - 4 \right)\) shifts the graph downwards by 4 units. Considering the graph provided, the correct function that matches the graph is: **C) \( g(x) = \frac{1}{3}x^2 - 4 \)** The graph shows a parabola opening upwards with a vertex at (0, -4), which corresponds to the function \( g(x) = \frac{1}{3}x^2 - 4 \).
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