A rectangle is bounded by the x-axis and the parabola y=9-x². What length and width should the rectangle have to that its area is a maximum?

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem:**

A rectangle is bounded by the \(x\)-axis and the parabola \(y = 9 - x^2\). What length and width should the rectangle have so that its area is a maximum?

**Diagram Explanation:**

The diagram shows a parabola opening downwards, with its vertex at the point (0, 9) on the \(y\)-axis. The parabola intersects the \(x\)-axis at points (-3, 0) and (3, 0). The rectangle is inscribed such that its base lies along the \(x\)-axis, with the top touching the parabola.

To find the maximum area of the rectangle, one must find the dimensions (length and width) where the area \(A = \text{length} \times \text{width}\) is largest. The length of the rectangle is along the \(x\)-axis, while the width is constrained by the parabola.
Transcribed Image Text:**Problem:** A rectangle is bounded by the \(x\)-axis and the parabola \(y = 9 - x^2\). What length and width should the rectangle have so that its area is a maximum? **Diagram Explanation:** The diagram shows a parabola opening downwards, with its vertex at the point (0, 9) on the \(y\)-axis. The parabola intersects the \(x\)-axis at points (-3, 0) and (3, 0). The rectangle is inscribed such that its base lies along the \(x\)-axis, with the top touching the parabola. To find the maximum area of the rectangle, one must find the dimensions (length and width) where the area \(A = \text{length} \times \text{width}\) is largest. The length of the rectangle is along the \(x\)-axis, while the width is constrained by the parabola.
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