Match List-I (The impulse response) with List-II (Causality and stability which corresponds to the impulse response) and choose the correct answer using the given choices below: List-I(Impulse response) e cos (21)u(-t) List-II(Causality &Stability) 1. Causal & stable G u (n) [5(n)-8(n-2)] Q. 2. Causal & Unstable te"u(-t-3) 3. Non-causal & Stable 1 - пе "u (п) S. 4. Non-causal & Unstable Answer Choices: a. P→ 4,Q→ 2,R → 3, S →1 b. P→ 3,Q →1,R →3,S –→1 c. P→ 3,Q →1,R → 4,S –→ 2 d. P→3,Q –→1,R → 4,S→1 P. R.

Match List-I (The impulse response) with List-II (Causality and stability which corresponds to the impulse response) and choose the correct answer using the given choices below: List-I(Impulse response) e cos (21)u(-t) List-II(Causality &Stability) 1. Causal & stable G u (n) [5(n)-8(n-2)] Q. 2. Causal & Unstable te"u(-t-3) 3. Non-causal & Stable 1 - пе "u (п) S. 4. Non-causal & Unstable Answer Choices: a. P→ 4,Q→ 2,R → 3, S →1 b. P→ 3,Q →1,R →3,S –→1 c. P→ 3,Q →1,R → 4,S –→ 2 d. P→3,Q –→1,R → 4,S→1 P. R.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Find the value of K to yield a static error constant of 10,000.
Hello Sir.Good Evening. I have a question in my home work related Control System Lesson. The following below is my question.Please advise, Thank you so much.
What is the impulse response of the difference equation below: y[n] = ax[n−3] − by [n−1] y[n] = ax[n−3] − by[n−1].
Hand written please.
Q1: For the causal system shown in the figure below (a) Find and sketch, the first five samples of the impulse response A[n] and step response s[n] (b) Determine the final value of s[n] as n—oo (c) Find the response to a rectangular pulse input with pulse duration equal 5. x[n] 0 yln] — —> T (05)—
QUESTION 2 Two systems, h, [n] and h,[n] are connected in series and parallel with a system, h,[n] as shown in Figure Q2. The LTI impulse response functions of the systems h[n], ha[n] and ha[n] are given by equations (1), (2) and (3), respectively. h [n] = 2nu[n + 2] – 2nu[n – 3] (1) h2[n] = -3(u[n + 1] – u[n – 31) (2) %3D hz[n] = -2u[n – 1] + 2u[n – 5] (3) y[n] x,[n] Yı [n] h,[n] yz[n] h[n] x2[n] Ya[r] ha[n] Figure Q2 (a) Analyse the output response of y,[n] using convolution if the input signal x, [n] is given by x, [n] = 6[n + 4]. You may use any methods to obtain the output. Sketch the output signal y, [n].
Control Systems
Consider the integrator circuit shown below. From the input and output graphs shown, determine if this circuit is working correctly, by first determining what the output should be. (Show your working/reasoning.) The output of the integrator shown is given below: Vout Vindt RC The general form of the integral (assuming the input is a cosine) is given by: A A cos(wt)dt = – sin(wt) 100k? 0.2µF 2.2k2 Vout 300 Hz - Output = 3.13 V, PP Input 2.0 V Pp -2 -3 1. 3. 6. 8. 9. 10 Time / [ms] 2. 3. Input/Output Voltage / [V]
DO NOT COPY FROM OTHER WEBSITES Correct and detailed answer will be Upvoted else downvoted. Thank you!
4. a) Find the complete solution for the difference equation y[n] – 0.9y[n-1] = x[n] with the input x[R]= (-1/4)"u[n] and initial condition y[-1]= 1. b) An LTI system has an impulse response h[n] and input x[n] displayed in Figure 2 below. (b.i) Apply the method of convolution by superposition to find and sketch the convolution output y[n] of the system. (b.ii) Determine and sketch the step response of this LTI system.
Consider an input x[n] and a unit impulse response h[n] given by x[n] = (½)n-2 u[n- 2], h[n] = u[n-2]Determine and plot the output y[n] = x[n] * h[n]( NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE).
Feedback & Control Systems Reduction of Multiple Subsystems