A nutrition expert claims that the average American is overweight. To test his claim, a random sample of 20 Americans was selected, and the difference between each person's actual weight and ideaweight was calculated. For this data, we have17.3 and s28.9. Is there sufficient evidence to conclude that the expert's claim is true? Carry out a hypothesis test at a 3% significance level. Hint: Payattention to the variable being measured: the difference between actual weight and ideal. A positive value indicates that the person is overweight.A. The value of the standardized test statistic (give to 3 decimal places):B. The p-value is (give to 4 decimal places):C. Your decision for the hypothesis test:O A. Reject H..B. Do Not Reject Ho-O C. Do Not Reject HaD. Reject Ho.

Given data : sample size, n = 20 sample mean, x̄ = 17.3 sample standard…

Answered: mat he average Afferican is overweight.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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a. The null hypothesis ?ob. The alternative hypothesis ?ac. The level of significance ?
A diet doctor claims that the average North American is more than 20 poundsoverweight. To test this claim, a random sample of 20 North Americans was weighed,and the difference between their actual and ideal weights was calculated. The statisticscalculated from the sample were ?̅= 21.2 and ? = 6.7. Do these data allow us to infer atthe 6% significance level that the doctor’s claim is true? Provide your analysis andconclusion.
can you please answer: G, H, I
The following details are available with regard to a test of hypothesis for the population mean: H0:μ = 60, σ = 60 x̅ = 72, test statistic = 1.20 what is the sample size?
A nutrition expert claims that the average American is overweight. To test his claim, a random sample of 29 Americans was selected, and the difference between each person's actual weight and idea weight was calculated. For this data, we have x = 15.7 and s = 29.9. Is there sufficient evidence to conclude that the expert's claim is true? Carry out a hypothesis test at a 9% significance level. Hint: Pay attention to the variable being measured: the difference between actual weight and ideal. A positive value indicates that the person is overweight. %3D A. The value of the standardized test statistic (give to 3 decimal places): B. The p-value is (give to 4 decimal places): C. Your decision for the hypothesis test: O A. Reject Ho. O B. Do Not Reject Ho. C. Do Not Reject Ha. O D. Reject Ha.
Elliot was curious if there was a relationship between a student's gender and what superpower they'd prefer to have. He obtained data from a random sample of 206 students. Here is a summary of the data and the results from a chi-square test: Chi-square test: Superpower vs. gender Female Male Fly 19 32 Expected 27.73 23.27 Freeze time 17 23 Expected 21.75 18.25 Invisibility 23 13 Expected 19.57 16.43 Telepathy 53 26 Expected 42.95 36.05 X = 14.759, DF = 3, P-value = 0.002 %3D Assume that all conditions for inference were met. At the a = 0.05 significance level, what is the most appropriate conclusion to draw from this test?
Using image attached A. Fill in blanks B. What are the null and alternative hypothesis? C. Find the test statistic, z0 D. Find the P-Value
According to the most recent General Social Survey, 70% of adults watch TV nightly. A researcher believes that the proportion of college students who watch TV nightly is less than this. To test this claim the research samples 400 college students and finds that 276 watch TV nightly. At the 0.05 level of significance does this data provide evidence to suggest that the proportion of college students who watch TV nightly is less than 70%? Select the correct hypothesis test for this problem:
Before the semester began, Professor Keithley predicted that 15% of hisphilosophy students would receive an A, 30% a B, 40% a C, 10% a D, and 5%an F. At the end of the semester, 14 of Professor Keithley’s philosophy studentsearned an A, 19 a B, 12 a C, 5 a D, and 2 an F.Use the Chi-Square test and a 0.05 level of significance to determine if ProfessorKeithley’s predicted percentages were accurate. (State your null and alternativehypothesis, find the critical values and test statistics, make a decision, and writea conclusion based on your results).
Suppose ?1 and ?2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. Use the two-sample t test at significance level 0.01 to test H0: ?1 − ?2 = −10 versus Ha: ?1 − ?2 < −10 for the following data: m = 8, x = 114.8, s1 = 5.01, n = 8, y = 129.9, and s2 = 5.35. Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.)
A nutrition expert claims that the average American is overweight: To test his claim, a random sample of 25 Americans was selected, and the difference between each person's actual weight and idea weight was calculated. For this data, we have = 16 and 8 = 28.4. Is there sufficient evidence to conclude that the expert's claim is true? Carry out a hypothesis test at a 8% significance level. Hint: Pay attention to the variable being measured: the difference between actual weight and ideal. A positive value indicates that the person is overweight. A. The value of the standardized test statistic (give to 3 decimal places): B. The p-value is (give to 4 decimal places): C. Your decision for the hypothesis test: O A. Reject Ho- OB. Reject Ha C. Do Not Reject Ha- O D. Do Not Reject Ho- E
Test the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: H20; a=0.10. Sample statistics: d= -2.4, sd = 1.2, n = 15 Identify the null and alternative hypotheses. Choose the correct answer below. OA. Ho Hd #0 Ha Hg=0 OC. Ho Hd=0 Ha Hd #0 E. Ho Hd 20 Ha Hd 0 OD. Ho: Hy >0 Ha Hd ≤0 OF. Ho Hd <0 Ha Ha 20

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