**Educational Website Content: Hypothesis Testing****Overview:**The scenario being examined is whether the mean number of Facebook friends is greater than 125, given a population standard deviation and a sample of high school students.**Details:**1. **Statement of Hypotheses:** - Null Hypothesis (\(H_0\)): The mean number of Facebook friends is 125. - Alternative Hypothesis (\(H_1\)): The mean number of Facebook friends is greater than 125. This is a right-tailed test, as the alternative hypothesis focuses on whether the mean is greater than 125.2. **Critical Value:** - Determine the critical value(s) for the z-test at \(\alpha = 0.10\). - Critical values are where the decision to reject or fail to reject the null hypothesis is made. - Enter the calculated critical value rounded to two decimal places.3. **Test Statistic:** - Calculate the z-test statistic to compare against the critical value. - Use the formula for the z-test: \[ z = \frac{\bar{x} - \mu}{\sigma / \sqrt{n}} \] - Round the z score to two decimal places for consistency in decision-making.4. **Conclusion:** - Evaluate the computed z score against the critical value to determine if the null hypothesis should be rejected. - If the z score is greater than the critical value, the null hypothesis is rejected, indicating that the mean number of friends is statistically greater than 125.This content guides you through the hypothesis testing process step by step, demonstrating how to verify claims using statistical methods. The image contains two sections related to hypothesis testing.### Part 4 of 5- **Make the decision.** - Dropdown menu: "(Choose one)" - Text: "the null hypothesis."### Part 5 of 5- **Summarize the results.** - Sentence: "There (Choose one) enough evidence to support the claim that the mean number of Facebook friends is greater than 125." Both sections have interactive elements like dropdown menus to allow users to select their responses. There are progress indicators in the form of blue bars showing that this is part of a multi-step process.

From the provided information, Sample size (n) = 36 Sample mean (x̄) = 151 Population standard…

Answered: Many people believe that the average…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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We are interested in seeing if there is a difference between how long women and men spend shopping at Costko-K. Men spend an average of 48 minutes in our store with a standard deviation of 22 minutes. Women spend an an average of 39 minutes in our store with a standard deviation of 9 minutes. The sample size for men is 250 and the sample size for women is 300. Test the hypothesis at a 95% confidence level. Show your calculations and explain your findings.
Two species of fish have similar phenotypes to each other, researchers wonder if they can classify these fish species based on their sizes. One species has mean size of 10cm, with standard deviation of 1. The other species has mean size of 12cm, with standard deviation of 2. Size of 15 fish from each species were measured. a. Which hypothesis testing method can be used to compare the mean size of the two populations? Perform the test for a = 0.01. How does result of this test help the researchers to decide if they can classify these fish species based on their sizes? b. What is the power of the test? How does power of the test help the researchers to decide if they can classify these fish species based on their sizes?
One question from a survey was "How many credit cards do you currently have?" The results of the survey are provided. 32233513522533835234327323453222222732235294123342210344237213331529236224214332243113433117131321241 Determine the standard deviation number of credit cards based on the raw data.The standard deviation is how many credit cards?
According to the American Time Use Survey, the typical American spends 183 minutes per day watching television. A college dean wondered if college students were different. He conducted a survey of 50 college students and found they had a mean of 165 minutes per day with a standard deviation of 72. To test this hypothesis, find P-value and rind to the nearest thousandth. Using the a=0.05, write a conclusion for the hypothesis test for question above, state whether or not you are rejecting hypothesis and what the hypothesis is in words, write a sentence that the researcher could share with colleagues without using technical terms for statistics
A random sample of 49 cans of soda is obtained and the contents are measured. The sample mean is 12.01 oz and the standard deviation is 0.13 oz. Test the claim that the contents of all such cans have a mean different from 12.00 oz, as indicated by the label. Use a 0.05 significance level. Find the Z score And the P value. Do you reject the hypothesis?
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An archer’s standard deviation for his hits is six (data is measured in distance from the center of the target). An observer claims the standard deviation is less.a. What type of test should be used?b. State the null and alternative hypotheses.c. Is this a right-tailed, left-tailed, or two-tailed test?
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The mean ACT score for 43 male high school students is 21.1 and the standard deviation is 5.0. The mean ACT score for 56 female high school students is 20.9 and the standard deviation is 4.7. At the 1% significance level, can you reject the claim that male and female high school students have equal ACT score averages? Be sure to use the p-value to make your conclusion.
It is believed that nearsightedness affects 14% of children in a certain region. A school district tests the vision of 180 incoming kindergarten children. How many would be expected to be nearsighted? What is the standard deviation for the number of nearsighted children in such a group? You may assume that the children are independent of each other. The mean is? and the standard deviation is?
Two species of fish have similar phenotvpes to each other, researchers wonder if they can classify these fish species based on their sizes. One species has mean size of 10cm, with standard deviation of 1. The other species has mean size of 12cm, with standard deviation of 2. Size of 15 fish from each species were measured. a. Which hypothesis testing method can be used to compare the mean size of the two populations? Perform the test for a = 0.01. How does result of this test help the researchers to decide if they can classify these fish species based on their sizes?
The composite ACT scores for Idaho students who took the test in 2019 have average 22.3 with the standard deviation 2.25 and approximately normal distributed. In a random sample of 49 students who took the exam in 2019, the average composite ACT score is 23.5 with standard deviation 1.06. (show your work) Which one is true? 3 and 2.25 are statistics, and 1.06 are parameters. 3 and 2.25 are parameters, and 1.06 are statistics. All numbers 22.3, 2.25 and 23.5, 1.06 are parameters. All numbers 22.3, 2.25 and 23.5, 1.06 are statistics. What is the probability that the score is 23 or more if we random select one student? Find the 85th percentile the composite ACT scores for Idaho students

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