A golf analyst claims that the standard deviation of the 18-hole scores for a golfer is at least 3.5 strokes. State Ho and Ha in words and in symbols. Then determine whether the hypothesis test for this claim is left-tailed, right-tailed, or two-tailed. Explain your reasoning. OA. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at most 3.5 strokes." The null hypothesis is expressed symbolically as, "Ho: 0≤3.5." OB. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at least 3.5 strokes." The null hypothesis is expressed symbolically as, "H:023.5." OC. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is not 3.5 strokes." The null hypothesis is expressed symbolically as, "Ho: 03.5." OD. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is equal to 3.5 strokes." The null hypothesis is expressed symbolically as, "H₁:0=3.5."
A golf analyst claims that the standard deviation of the 18-hole scores for a golfer is at least 3.5 strokes. State Ho and Ha in words and in symbols. Then determine whether the hypothesis test for this claim is left-tailed, right-tailed, or two-tailed. Explain your reasoning. OA. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at most 3.5 strokes." The null hypothesis is expressed symbolically as, "Ho: 0≤3.5." OB. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at least 3.5 strokes." The null hypothesis is expressed symbolically as, "H:023.5." OC. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is not 3.5 strokes." The null hypothesis is expressed symbolically as, "Ho: 03.5." OD. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is equal to 3.5 strokes." The null hypothesis is expressed symbolically as, "H₁:0=3.5."
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![A golf analyst claims that the standard deviation of the 18-hole scores for a golfer is at least 3.5 strokes. State Ho and
Ha in words and in symbols. Then determine whether the hypothesis test for this claim is left-tailed, right-tailed,
or two-tailed. Explain your reasoning.
OA. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer
is at most 3.5 strokes." The null hypothesis is expressed symbolically as,
"Ho: 0≤3.5."
OB. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer
is at least 3.5 strokes." The null hypothesis is expressed symbolically as,
"Η: 623.5."
OC. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is not
3.5 strokes." The null pothesis is expressed symbolically as,
"H: #3.5."
OD. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer
is equal to 3.5 strokes." The null hypothesis is expressed symbolically as,
"Ho: o=3.5."
lp](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2c74e54b-a92f-4876-b3fa-8f0907fc3ccf%2F64c8d964-6954-41ac-9ee0-5f1295b693c9%2F16c0ig_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A golf analyst claims that the standard deviation of the 18-hole scores for a golfer is at least 3.5 strokes. State Ho and
Ha in words and in symbols. Then determine whether the hypothesis test for this claim is left-tailed, right-tailed,
or two-tailed. Explain your reasoning.
OA. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer
is at most 3.5 strokes." The null hypothesis is expressed symbolically as,
"Ho: 0≤3.5."
OB. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer
is at least 3.5 strokes." The null hypothesis is expressed symbolically as,
"Η: 623.5."
OC. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is not
3.5 strokes." The null pothesis is expressed symbolically as,
"H: #3.5."
OD. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer
is equal to 3.5 strokes." The null hypothesis is expressed symbolically as,
"Ho: o=3.5."
lp
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