The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces.The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.2 ounces.Suppose that you draw a random sample of 42 cans. Part i) Suppose the number of cans drawn is doubled. How will the standard deviation of sample mean weight change?A. It will increase by a factor of 2.B. It will decrease by a factor of 2.C. It will increase by a factor of 2–√2.D. It will decrease by a factor of 2–√2.E. It will remain unchanged.Part ii) Suppose the number of cans drawn is doubled. How will the mean of the sample mean weight change?A. It will decrease by a factor of 2.B. It will increase by a factor of 2.C. It will increase by a factor of 2–√2.D. It will decrease by a factor of 2–√2.E. It will remain unchanged.Part iii) Consider the statement: 'The distribution of the mean weight of the sampled cans of Ocean brand tuna is Normal.'A. It is a correct statement, and it is a result of the Central Limit Theorem.B. It is an incorrect statement. The distribution of the mean weight of the sample is not Normal.C. It is a correct statement, but it is not a result of the Central Limit Theorem. Part i) Suppose the number of cans drawn is doubled. How will the standard deviation of sample mean weight change?A. It will increase by a factor of 2.B. It will decrease by a factor of 2.C. It will increase by a factor of √2.D. It will decrease by a factor of √2.E. It will remain unchanged.Part ii) Suppose the number of cans drawn is doubled. How will the mean of the sample mean weight change?A. It will decrease by a factor of 2.B. It will increase by a factor of 2.C. It will increase by a factor of √2.D. It will decrease by a factor of √/2.E. It will remain unchanged.Part iii) Consider the statement: 'The distribution of the mean weight of the sampled cans of Ocean brand tuna is Normal.'A. It is a correct statement, and it is a result of the Central Limit Theorem.B. It is an incorrect statement. The distribution of the mean weight of the sample is not Normal.C. It is a correct statement, but it is not a result of the Central Limit Theorem. The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.2 ounces. Suppose that you draw a random sample of 42

Provided information is ; Let , X be the net weight Population mean(μ) = 5.95 Population standard…

The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.2 ounces. Suppose that you draw a random sample of 42 cans. Part i) Suppose the number of cans drawn is doubled. How will the standard deviation of sample mean weight change? A. It will increase by a factor of 2. B. It will decrease by a factor of 2. C. It will increase by a factor of 2–√2. D. It will decrease by a factor of 2–√2. E. It will remain unchanged. Part ii) Suppose the number of cans drawn is doubled. How will the mean of the sample mean weight change? A. It will decrease by a factor of 2. B. It will increase by a factor of 2. C. It will increase by a factor of 2–√2. D. It will decrease by a factor of 2–√2. E. It will remain unchanged. Part iii) Consider the statement: 'The distribution of the mean weight of the sampled cans of Ocean brand tuna is Normal.' A. It is a correct statement, and it is a result of the Central Limit Theorem. B. It is an incorrect statement. The distribution of the mean weight of the sample is not Normal. C. It is a correct statement, but it is not a result of the Central Limit Theorem.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces.

The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.2 ounces.

Suppose that you draw a random sample of 42 cans.

Part i) Suppose the number of cans drawn is doubled. How will the standard deviation of sample mean weight change?

A. It will increase by a factor of 2.
B. It will decrease by a factor of 2.
C. It will increase by a factor of 2–√2.
D. It will decrease by a factor of 2–√2.
E. It will remain unchanged.

Part ii) Suppose the number of cans drawn is doubled. How will the mean of the sample mean weight change?

A. It will decrease by a factor of 2.
B. It will increase by a factor of 2.
C. It will increase by a factor of 2–√2.
D. It will decrease by a factor of 2–√2.
E. It will remain unchanged.

Part iii) Consider the statement: 'The distribution of the mean weight of the sampled cans of Ocean brand tuna is Normal.'

A. It is a correct statement, and it is a result of the Central Limit Theorem.
B. It is an incorrect statement. The distribution of the mean weight of the sample is not Normal.
C. It is a correct statement, but it is not a result of the Central Limit Theorem.

Transcribed Image Text:Part i) Suppose the number of cans drawn is doubled. How will the standard deviation of sample mean weight change? A. It will increase by a factor of 2. B. It will decrease by a factor of 2. C. It will increase by a factor of √2. D. It will decrease by a factor of √2. E. It will remain unchanged. Part ii) Suppose the number of cans drawn is doubled. How will the mean of the sample mean weight change? A. It will decrease by a factor of 2. B. It will increase by a factor of 2. C. It will increase by a factor of √2. D. It will decrease by a factor of √/2. E. It will remain unchanged. Part iii) Consider the statement: 'The distribution of the mean weight of the sampled cans of Ocean brand tuna is Normal.' A. It is a correct statement, and it is a result of the Central Limit Theorem. B. It is an incorrect statement. The distribution of the mean weight of the sample is not Normal. C. It is a correct statement, but it is not a result of the Central Limit Theorem.

Transcribed Image Text:The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.2 ounces. Suppose that you draw a random sample of 42

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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