Manually trace the following code to analyze how it works #include using namespace std; int main() {     int n = 5;     for (int row = 0; row < n; row++) {           for (int col = 0; col < n; col++) {                  cout << "*";        }         cout << endl; } } Based on the above s SquareCode, generate a code fragment “firstTriangle” in your main()  that reads in an integer n and displays the following triangle assuming n=5. The only couts you may use are cout <<“*” and cout << endl; Hint: write out a table showing for each row, how may columns you will need to display. * ** *** **** *****

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