Male Female n1= 12 n2= 8 M1= 99.17 M2 = 67.25 %3D SS3= 62.73 SS2 = 38.297 %3D df = n, +n2 - 2 = 12 +8-2 df = 18 Level a = 0.10 A) The null hypothesis ( Ho): 2 = 0 B) The alternative hypathesis ( H1 ) :1 - H, # 0 C) The critical value : t = ± 2.101
Male Female n1= 12 n2= 8 M1= 99.17 M2 = 67.25 %3D SS3= 62.73 SS2 = 38.297 %3D df = n, +n2 - 2 = 12 +8-2 df = 18 Level a = 0.10 A) The null hypothesis ( Ho): 2 = 0 B) The alternative hypathesis ( H1 ) :1 - H, # 0 C) The critical value : t = ± 2.101
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:SS+SS2 70.22+78
dfi+df2
148.22
Pooled variance: S,
= 8.23
This is just a sample!
11+7
18
s2
S2
8.23
8.23
Estimated standard error: S (M,-M)=
n1
n2
12
8.
=Vo. 69 + 1.03 = V1.72 = 1.31(you will have different
%3D
answer)
= -2.48 (you will have
1.31
12.5-15.75-0
-3.25
(M1-M2)-(H1-Kz) _
S(M1-M2)
The t statistics: t =
1.31
different answer)
The test statistics: Z, = -2.48 (you will have different answer)

Transcribed Image Text:Font
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Hypothesis test:
Male
Female
n1= 12
n2= 8
M = 99.17
M2 = 67.25
SS,= 62.73
SS2 = 38.297
df = n1 +n2 - 2
= 12 +8-2
%3D
df = 18
Level a = 0.10
A) The null hypothesis ( Ho ): H1-42 = 0
B) The alternative hypothesis ( H) 1- H2 0
C)
The critical value :
t = 2.101
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