M2V2 M1 where M1 and Vi are the initial concentration and volume, respectively, and M, and V2 represent the final co and volume, respectively. A student needs to prepare 50.0 mL of 1.10 M aqueous H,O, solution from 4.9 M H,O, stock solution. Set u equation to solve for the volume of stock solution needed by plugging the given values into the equation. M mL Vị = M

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please help with all the parts in this question, it is practice so I want to have all the parts to study

The dilution equation, rearranged to solve for \( V_1 \), is 

\[ V_1 = \frac{M_2 V_2}{M_1} \]

where \( M_1 \) and \( V_1 \) are the initial concentration and volume, respectively, and \( M_2 \) and \( V_2 \) represent the final concentration and volume, respectively.

A student needs to prepare 50.0 mL of 1.10 M aqueous \( \text{H}_2\text{O}_2 \) solution from 4.9 M \( \text{H}_2\text{O}_2 \) stock solution. Set up an equation to solve for the volume of stock solution needed by plugging the given values into the equation.

\[ V_1 = \frac{1.10 \, \text{M} \times 50.0 \, \text{mL}}{4.9 \, \text{M}} \]
Transcribed Image Text:The dilution equation, rearranged to solve for \( V_1 \), is \[ V_1 = \frac{M_2 V_2}{M_1} \] where \( M_1 \) and \( V_1 \) are the initial concentration and volume, respectively, and \( M_2 \) and \( V_2 \) represent the final concentration and volume, respectively. A student needs to prepare 50.0 mL of 1.10 M aqueous \( \text{H}_2\text{O}_2 \) solution from 4.9 M \( \text{H}_2\text{O}_2 \) stock solution. Set up an equation to solve for the volume of stock solution needed by plugging the given values into the equation. \[ V_1 = \frac{1.10 \, \text{M} \times 50.0 \, \text{mL}}{4.9 \, \text{M}} \]
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