J 7 m=120 incomePrice = 24 → X, good ILe•P₂ = 3€ →→ X₂ good 23/5U (X₁, X₂) = x₁²/5x₂3-3/S3/5SollutionauMRS = 2x₁quX215X ₂axatheHanget conditionP₁ = 2X₂P₂3X₁we solve the equations³p₁x₁=2p₂X₂P₁ X₁ +P₂X₂ = mthe solutionis:2mSpix₂ = 2mSP₂Substituting prices for income and prices of goods in thisbe the sollution is:how found 24?X₁₂₁ = 24 and 7₁₂=24Please explaine to me step by step thesollution of this exercise so that I canunderstand how the result was foundWDATA-2/52 Xe3x1

For this we already have equation as : 3p1x1=2p2x2 -----(1)and p1x1+p2x2=m------(2)

m=120 income = 2* →> x₁ good I \p₁₂ = 3€ →→x₂ good 2 3/5 U (X₁, X₂) = x, 2/5x₂3 Price P au Sollution MRS = ax X, 215 X₂ axa the Hanget condition P₁ = 2X₂ P₂ 3X₁ we solve the equations ³p₁x₁=2p₂X₂ P₁ X₁ + P₂X₂ = m the sollutionis: 2m Spi x₂ = 2m SP 2 Substituting prices for income and prices of goods in this be the sollution is: how found 24? X₁₂₁ = 24 and 7₁₂=24 Please explaine to me step by step the sollution of this exercise so that I can understand how the result was found W -3/5 3/5 DATA -2/5 2 Xe 3x1

m=120 income = 2* →> x₁ good I \p₁₂ = 3€ →→x₂ good 2 3/5 U (X₁, X₂) = x, 2/5x₂3 Price P au Sollution MRS = ax X, 215 X₂ axa the Hanget condition P₁ = 2X₂ P₂ 3X₁ we solve the equations ³p₁x₁=2p₂X₂ P₁ X₁ + P₂X₂ = m the sollutionis: 2m Spi x₂ = 2m SP 2 Substituting prices for income and prices of goods in this be the sollution is: how found 24? X₁₂₁ = 24 and 7₁₂=24 Please explaine to me step by step the sollution of this exercise so that I can understand how the result was found W -3/5 3/5 DATA -2/5 2 Xe 3x1

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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