330/100=3.3. Assuming 100 individuals is clearly arbitrary, and the mean could also Here are 100 individuals, the mean store number is (301)+(20 x 2)+(10 x 3) + be found by weighting the store numbers directly by their probabilities: (0.3 x 1) + (0.2 x 2) + (0.1 x 3) + (0.1 x 5) + (0.3 x 6) = 3.3. Our estimate of L is equal to 1/3.3 or 0.303. EXERCISES 1. Snowfall for a location is found to be normally distributed with mean 96" and standard deviation of 32". (a) What is the probability that a given year will have more than 120" of snow? (b) What is the probability that the snowfall will be between 90" and 100"? (c) What level of snowfall will be exceeded only 10% of the time? 2. Assume that the prices paid for housing within a neighborhood have a normal distribution, with mean $100,000, and standard deviation of $35,000. (a) What percentage of houses in the neighborhood have prices between $90,000 and $130,000? (b) What price of housing is such that only 12% of all houses in the neighborhood have lower prices? (Continued)
330/100=3.3. Assuming 100 individuals is clearly arbitrary, and the mean could also Here are 100 individuals, the mean store number is (301)+(20 x 2)+(10 x 3) + be found by weighting the store numbers directly by their probabilities: (0.3 x 1) + (0.2 x 2) + (0.1 x 3) + (0.1 x 5) + (0.3 x 6) = 3.3. Our estimate of L is equal to 1/3.3 or 0.303. EXERCISES 1. Snowfall for a location is found to be normally distributed with mean 96" and standard deviation of 32". (a) What is the probability that a given year will have more than 120" of snow? (b) What is the probability that the snowfall will be between 90" and 100"? (c) What level of snowfall will be exceeded only 10% of the time? 2. Assume that the prices paid for housing within a neighborhood have a normal distribution, with mean $100,000, and standard deviation of $35,000. (a) What percentage of houses in the neighborhood have prices between $90,000 and $130,000? (b) What price of housing is such that only 12% of all houses in the neighborhood have lower prices? (Continued)
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
Related questions
Question
Qn 2 use z table no excel
![there
urbs
e
St
n
330/100 = 3.3. Assuming 100 individuals is clearly arbitrary, and the mean could also
DINICO Here are 100 individuals, the mean store number is
(30× 1) + (20 x 2) + (10 x 3) +
be found by weighting the store numbers directly by their probabilities: (0.3 x 1) + (0.2 x
2) + (0.1 x 3) + (0.1 x 5) + (0.3 x 6) = 3.3. Our estimate of L is equal to 1/3.3 or 0.303.
1.
EXERCISES
Snowfall for a location is found to be normally distributed with mean 96" and
standard deviation of 32".
(a) What is the probability that a given year will have more than 120" of snow?
(b) What is the probability that the snowfall will be between 90" and 100"?
(c) What level of snowfall will be exceeded only 10% of the time?
2. Assume that the prices paid for housing within a neighborhood have a normal
distribution, with mean $100,000, and standard deviation of $35,000.
(a) What percentage of houses in the neighborhood have prices between $90,000
and $130,000?
(b) What price of housing is such that only 12% of all houses in the neighborhood
have lower prices?
(Continued)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F320a6a87-d7c1-4be3-9228-d5dac0637446%2F9aec7d0d-1b7c-4262-b3dd-0c3473d60f25%2Feav46qq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:there
urbs
e
St
n
330/100 = 3.3. Assuming 100 individuals is clearly arbitrary, and the mean could also
DINICO Here are 100 individuals, the mean store number is
(30× 1) + (20 x 2) + (10 x 3) +
be found by weighting the store numbers directly by their probabilities: (0.3 x 1) + (0.2 x
2) + (0.1 x 3) + (0.1 x 5) + (0.3 x 6) = 3.3. Our estimate of L is equal to 1/3.3 or 0.303.
1.
EXERCISES
Snowfall for a location is found to be normally distributed with mean 96" and
standard deviation of 32".
(a) What is the probability that a given year will have more than 120" of snow?
(b) What is the probability that the snowfall will be between 90" and 100"?
(c) What level of snowfall will be exceeded only 10% of the time?
2. Assume that the prices paid for housing within a neighborhood have a normal
distribution, with mean $100,000, and standard deviation of $35,000.
(a) What percentage of houses in the neighborhood have prices between $90,000
and $130,000?
(b) What price of housing is such that only 12% of all houses in the neighborhood
have lower prices?
(Continued)
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