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μ = √√n(n+2) n =3 µ= √√√15 = 3.9 The complex A contains two cobalt(II) centres which are both octahedral and low spin (i.e there is one unpaired electron in the eg orbital. If n = 1 we might expect that each cobalt would have a magnetic moment of μ =√3 = 1.73. The complex would be paramagnetic. To get a diamagnetic complex the two unpaired electrons on each cobalt would have to spin-pair which can be achieved by antiferromagnetic coupling.

μ = √√n(n+2) n =3 µ= √√√15 = 3.9 The complex A contains two cobalt(II) centres which are both octahedral and low spin (i.e there is one unpaired electron in the eg orbital. If n = 1 we might expect that each cobalt would have a magnetic moment of μ =√3 = 1.73. The complex would be paramagnetic. To get a diamagnetic complex the two unpaired electrons on each cobalt would have to spin-pair which can be achieved by antiferromagnetic coupling.

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Is it possible to distinguish between paramagnetic and diamagnetic based on effective magnetic moment only? And please explain the interpretation below in more detail

 

μ = √√n(n+2) n=3 μ =√15 = 3.9 The complex A contains two cobalt(II) centres which are both octahedral and low spin (i.e there is one unpaired electron in the eg orbital. If n = 1 we might expect that each cobalt would have a magnetic moment of μ = √3 = 1.73. The complex would be paramagnetic. To get a diamagnetic complex the two unpaired electrons on each cobalt would have to spin-pair which can be achieved by antiferromagnetic coupling.
Transcribed Image Text:μ = √√n(n+2) n=3 μ =√15 = 3.9 The complex A contains two cobalt(II) centres which are both octahedral and low spin (i.e there is one unpaired electron in the eg orbital. If n = 1 we might expect that each cobalt would have a magnetic moment of μ = √3 = 1.73. The complex would be paramagnetic. To get a diamagnetic complex the two unpaired electrons on each cobalt would have to spin-pair which can be achieved by antiferromagnetic coupling.
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