MF_c__F_sF s'Eps_s'F sEps_sb_wClick to see additional instructionsFor C40 and S500, solve the given section with given parameters. Obtain correct resultsand fill the boxes with correspounding values.Note: Reinforcement number and diameters in drawing are exemplary. Use reinforcementnumbers and diameters given in parameters.Your Parameters;Concrete class = C40Steel class = S500Section height (h) = 550 mmSection width (b_w) = 300 mmBottom reinforcement = 4020Top reinforcement = 2020Stirrups = Ø10Section curvature (Kappa) = 0.015 rad/mYour answers;Concrete compression depth (c) =mTension reinforcement strain (Eps_s) =m/mkNTension reinforcement force (F_s) =Compression reinforcement strain (Eps_s') =m/mCompression reinforcement force (F_s') =|kNConcrete compression force (F_c) =kNSection force (N) =kNSection moment (M) =kNm

Solution; Given Data; bw=300 mmh=500 mmd=h-25-10-202=455 mmd'=25+10+202=45 mmAs=4-φ20=4*314=1256…

M _c s' s' Eps_s b_w Click to see additional instructions For C40 and S500, solve the given section with given parameters. Obtain correct results and fill the boxes with correspounding values. Note: Reinforcement number and diameters in drawing are exemplary. Use reinforcement numbers and diameters given in parameters. Your Parameters; Concrete class = C40 Steel class = 550o Section height (h) = 550 mm Section width (b_w) = 300 mm Bottom reinforcement = 4020 Top reinforcement = 2Ø20 Stirrups = Ø10 Section curvature (Kappa) = 0.015 rad/m Your answers; Concrete compression depth (c) = m Tension reinforcement strain (Eps_s) = m/m kN Tension reinforcement force (F_s) = Compression reinforcement strain (Eps_s') = m/m Compression reinforcement force (F_s') = kN Concrete compression force (F_c) = kN Section force (N) = kN Section moment (M) = kNm

M _c s' s' Eps_s b_w Click to see additional instructions For C40 and S500, solve the given section with given parameters. Obtain correct results and fill the boxes with correspounding values. Note: Reinforcement number and diameters in drawing are exemplary. Use reinforcement numbers and diameters given in parameters. Your Parameters; Concrete class = C40 Steel class = 550o Section height (h) = 550 mm Section width (b_w) = 300 mm Bottom reinforcement = 4020 Top reinforcement = 2Ø20 Stirrups = Ø10 Section curvature (Kappa) = 0.015 rad/m Your answers; Concrete compression depth (c) = m Tension reinforcement strain (Eps_s) = m/m kN Tension reinforcement force (F_s) = Compression reinforcement strain (Eps_s') = m/m Compression reinforcement force (F_s') = kN Concrete compression force (F_c) = kN Section force (N) = kN Section moment (M) = kNm

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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