Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.05significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. The chart for the data table of strontium is below. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. A. H0: μ1≤μ2 H1: μ1>μ2 B. H0: μ1=μ2 H1: μ1>μ2 C. H0: μ1=μ2 H1: μ1≠μ2 D. H0: μ1≠μ2 H1: μ1>μ2 The test statistic is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. A. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. C. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. D. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. More Info City #1 City #2 100 117 86 95 121 100 114 85 101 90 104 107 213 110 101 111 290 108 100 133 270 101 145 209
Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.05significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents. The chart for the data table of strontium is below. What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2. A. H0: μ1≤μ2 H1: μ1>μ2 B. H0: μ1=μ2 H1: μ1>μ2 C. H0: μ1=μ2 H1: μ1≠μ2 D. H0: μ1≠μ2 H1: μ1>μ2 The test statistic is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. A. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. C. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. D. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of strontium-90 from city #1 residents is greater. More Info City #1 City #2 100 117 86 95 121 100 114 85 101 90 104 107 213 110 101 111 290 108 100 133 270 101 145 209
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
Listed in the data table are amounts of strontium-90 (in millibecquerels, or mBq, per gram of calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.05significance level to test the claim that the mean amount of strontium-90 from city #1 residents is greater than the mean amount from city #2 residents.
The chart for the data table of strontium is below.
What are the null and alternative hypotheses? Assume that population 1 consists of amounts from city #1 levels and population 2 consists of amounts from city #2.
H1: μ1>μ2
H1: μ1>μ2
H1: μ1≠μ2
H1: μ1>μ2
The test statistic is
(Round to two decimal places as needed.)
The P-value is
(Round to three decimal places as needed.)
State the conclusion for the test.
More Info
|
|
|
City #1
|
City #2
|
|
---|---|---|
100
|
117
|
|
86
|
95
|
|
121
|
100
|
|
114
|
85
|
|
101
|
90
|
|
104
|
107
|
|
213
|
110
|
|
101
|
111
|
|
290
|
108
|
|
100
|
133
|
|
270
|
101
|
|
145
|
209
|
|
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