Listed in the data table are amounts of​ strontium-90 (in​ millibecquerels, or​ mBq, per gram of​ calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.05significance level to test the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater than the mean amount from city​ #2 residents. The chart for the data table of strontium is below. What are the null and alternative​ hypotheses? Assume that population 1 consists of amounts from city​ #1 levels and population 2 consists of amounts from city​ #2.     A. H0​: μ1≤μ2 H1​: μ1>μ2   B. H0​: μ1=μ2 H1​: μ1>μ2   C. H0​: μ1=μ2 H1​: μ1≠μ2   D. H0​: μ1≠μ2 H1​: μ1>μ2 The test statistic is   ​(Round to two decimal places as​ needed.) The​ P-value is   ​(Round to three decimal places as​ needed.) State the conclusion for the test.     A. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.   B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.   C. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.   D. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.   More Info     City #1 City #2   100 117   86 95   121 100   114 85   101 90   104 107   213 110   101 111   290 108   100 133   270 101   145 209

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Listed in the data table are amounts of​ strontium-90 (in​ millibecquerels, or​ mBq, per gram of​ calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.05significance level to test the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater than the mean amount from city​ #2 residents.
The chart for the data table of strontium is below.
What are the null and alternative​ hypotheses? Assume that population 1 consists of amounts from city​ #1 levels and population 2 consists of amounts from city​ #2.
 
 
A. H0​: μ1≤μ2
H1​: μ1>μ2
 
B. H0​: μ1=μ2
H1​: μ1>μ2
 
C. H0​: μ1=μ2
H1​: μ1≠μ2
 
D. H0​: μ1≠μ2
H1​: μ1>μ2
The test statistic is
 
​(Round to two decimal places as​ needed.)
The​ P-value is
 
​(Round to three decimal places as​ needed.)
State the conclusion for the test.
 
 
A. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.
 
B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.
 
C. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.
 
D. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.
 
More Info
 
 
City #1
City #2
 
100
117
 
86
95
 
121
100
 
114
85
 
101
90
 
104
107
 
213
110
 
101
111
 
290
108
 
100
133
 
270
101
 
145
209
 
 
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