The Newtower Company has experienced a 3.2% rate of customer complaints and attempts to lower this rate with an employment training program. After the program, the complaint rate is dropped to 1.5%. For a sample of 250 customers, find the mean and standard deviation for the number of complaints in this group of 250 customers. o² = 250 x 0.015 = 3.75,0 = 1.936 μ = 250+ 1.5 = 166.67 μ=150 o² = 250 x 0.015 x 0.985 = 3.694, o = 1.922 0²= 250 x 0.15 x 0.85 = 31.875,= 5.656

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The Newtower Company has experienced a 3.2% rate of customer complaints and attempts to
lower this rate with an employment training program. After the program, the complaint rate is
dropped to 1.5%. For a sample of 250 customers, find the mean and standard deviation for the
number of complaints in this group of 250 customers.
o² = 250 x 0.015 = 3.75,0 = 1.936
μ = 250 ÷ 1.5 = 166.67
μ = 150
o² = 250 x 0.015 x 0.985 = 3.694, o = 1.922
o² = 250 x 0.15 x 0.85 = 31.875, o = 5.656
Transcribed Image Text:The Newtower Company has experienced a 3.2% rate of customer complaints and attempts to lower this rate with an employment training program. After the program, the complaint rate is dropped to 1.5%. For a sample of 250 customers, find the mean and standard deviation for the number of complaints in this group of 250 customers. o² = 250 x 0.015 = 3.75,0 = 1.936 μ = 250 ÷ 1.5 = 166.67 μ = 150 o² = 250 x 0.015 x 0.985 = 3.694, o = 1.922 o² = 250 x 0.15 x 0.85 = 31.875, o = 5.656
Expert Solution
Step 1

Given, here it used binomial distribution where rate is equal to mean 1.5% = 0.015

We will use binomial distribution to find mean and variance.

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