Let X1,X2,...,X81 b
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A: H0 : μ = 36H1 : μ ≠ 36n = 31we have to identify which of the option will gve smallest p value.
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4. please use a .05 significance level for all the problems. Show all your work.
When you perform a test, you should at least tell me what your hypothesis is, the test
statistic and your conclusions based on your calculations.
Let X1,X2,...,X81 be i.i.d., each with
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- We are trying to predict GPA (Y) using number of hours spent studying (X1) and gender (X2). Our indicator variable for gender with male as the base is: If = {1 if Female} {0 else Our model is Y = Bo + B1X1+ B2IF + 8 } What is the expected value of Y if gender is female? O HF = Bo + B1X1 O µF = 0 O HF = Bo + 1 O uF = Bo + B1X1 + B2ts: Following are weights in pounds for random samples of 16 newborn baby boys and baby girls born in Denver in 2011 . Box plots indicate that the samples come from populations that are approximately normal. Let μ1 denote the mean weight of boys. Can you conclude that the mean weight of boys is less than the mean weight of girls? Use the =α0.05 level and the P -value method with the TI-84 Plus calculator. do we recject is there enough evidence Boys 7.8 7.6 6.4 7.7 7.8 7.4 5.9 6.6 6.9 6.9 7.5 6.3 6.4 6.4 6.4 7.7 Girls 7.0 6.7 8.5 7.2 6.7 7.4 8.1 7.7 6.9 8.2 8.2 7.7 8.2 7.5 7.2 8.2The nicotine content in cigarettes of a certain brand is normally distributed. The brand advertises that the mean nicotine content of their cigarettes is µ = 1.5, but measurements on a random sample of 100 cigarettes of this brand gave a mean of ?̅= 1.53 and s = 0.95. Is this evidence that the mean nicotine content is actually higher than advertised? 1. State the appropriate null and alternative hypotheses. H0: ? = 1.5 Ha: ? > 1.5 2. Should you use the z or t test? t – do not have sigma 3. Compute the test statistic to test your hypotheses. (report to 2 decimal places) ? = 1.53−1.5 0.95 √100 ⁄ = 0.32 4. Find the appropriate range of p-value for your test. P-value: a. Less than 0.005 b. Between 0.005 and 0.01 c. Between 0.01 and 0.025 d. Between 0.025 and 0.05 e. Greater than 0.05
- A population has a mean of µ = 20. A sample is selected from this population and a treatment is administered to each individual in the sample. The scores from this sample are summarized as follows: n = 16 ,X = 28 ,s2 = 64. Do the sample data support the conclusion that the treatment has a significant effect? Test with α = .05.How would u sovle thisYou are performing a right-tailed test.If α=.01α=.01, find the critical value, to three decimal places.zα =
- You have taken a random sample of sizen & 95of a normal population that has a population mean ofμ = 140and a population standard deviation ofo = 23. Your sample, which is Sample 1 in the following table, has a mean ofx = 141.3. (In the table, Sample 1 is indicated by "M1", Sample 2 by "M2", and so on.) (to) Based on Sample 1, plot the confidence intervals of80%and95%for the population mean. Use1,282as the critical value for the confidence interval of 80%and use1960 as the critical value for the confidence interval of95%. (If necessary, you can refer to a list of formulas .) • Write the upper limit and the lower limit on the graphs to indicate each confidence interval. Write the answers with one decimal place. • For the points (♦and ◆), write the population mean, μ = 140. 128.0 128.0 80% confidence interval 139.0 X Ś 150.0 150.0 128.0 128.0 95% confidence interval 139.0 X Ś 150.0 150.02. Suppose that we are testing Ho following observed values of the test (a) Zo= 2.45 (b) Zo= -1.53 = po versus H₁>po. Calculate the p-value for the statistic: (c) Zo= 2.15 (e) Zo= -0.35 (d) Zo = 1.95When testing the claim that the population mean is less than 12.8, suppose you get a test statistic of t= -0.92 and a P-value of 0.1818. What should we conclude about the claim? DII O There is sufficient evidence to warrant rejection of the claim. O There is not sufficient evidence to warrant rejection of the claim. O There is sufficient evidence to support the claim. O There is not sufficient evidence to support the claim. Submit Question F3 $ 4 R F4 % 5 T G B F5 6 H N F6 e & 7 U X M 8 PrtScn K 9 Home F9 End F10 Po
- 1. You are interested in the effect of a new learning technique. The performance score on the test before applying the new learning technique is 50 (u=50), the standard deviation is 4 (o=4). You obtained a sample of 64 subjects and applied the new learning technique. After that, their performance score on the test increased by 2 (x=52). Did the new learning technique improve/had any effect on the performance? The answer, using 4 steps of hypothesis testing. Please use APA style to report your result. Assume that a-level=.05 2. You are interested in the effect of a new learning technique. The performance score on the test before applying the new learning technique is 50 (u=50), the standard deviation is 24 (o=24). You obtained a sample of 64 subjects and applied the new learning technique. After that, their performance score on the test increased by 2 (x=52). Did the new learning technique improve/had any effect on the performance? The answer, using 4 steps of hypothesis testing.…A company is doing a hypothesis test on the variation of quality from two suppliers. Both distributions are normal, and the populations are independent. use a = 0.01 The standard deviation of the first sample is 3.3079 with a sample size of 21 and 4.5801 is the standard deviation of the second sample with a sample size of 12. The test statistic (rounded to 3 decimal places) is = O Fail to reject the null hypothesis O Reject the null hypothesisndependent random samples are selected from two populations and are used to test the hypothesis Hn: (H, - H2) = 0 against the alternative H,: (4, - H2) #0. An analysis of 232 observations from population 1 and 311 from population 2 yielded p-value of 0.113. Complete parts a and b below. a. Interpret the results of the computer analysis. Use as0.10. A. Since this p-value exceeds the given value of a, there is insufficient evidence to indicate that the population means are different. O B. Since the given a value exceeds this p-value, there is insufficient evidence to indicate that the population means are different. OC. Since the given a value exceeds this p-value, there sufficient evidence to indicate that the population means are different. O D. Since this p-value exceeds the given value of , there is sufficient evidence to indicate that the population means are different. b. If the alternative hypothesis had been Ha: (H1 - H2) <0, how would the p-value change? Interpret the p-value…