#3. A member of the Santa Cruz, California business community wants to know if local employees take a differentnumber of paid days off (e.g., vacation, sick leave) than the national average. The mean paid days off for 8 localemployees is 15.74 with a standard deviation 5.80. The national average is 10.38. Use alpha = 0.01 in this test ofhypothesis.%3D%3DSTEP 1. Identify the variable, names of the groups being compared, and numerical information provided.Variable:Population/condition of interest:Comparison population/condition:STEP 2. State the research and null hypotheses in words and symbolsResearch:Null:the nurSTEP 3. Characteristics of the comparison distribution.Identify/calculate the mean and standard deviation of thecomparison distribution. Label the distribution as shown in class.-3-2-12.3.STEP 4. Identify the critical value(s) for this test, label it (them) on the distribution, shade the rejection region(s).STEP 5. (a.) Calculate the test statistic, mark and label it on the comparison distribution. (b.) Use a Quick P-Valuecalculator (See Canvas > Modules > Formulas, Statistical Tables, and Applets > Applets) and write the exactp-value below. (c.) Calculate effect size.

T test is used to measure the mean significant relationship between the sample and population. It is…

Answered: #3. A member of the Santa Cruz,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average McDonald's restaurant generates $3.6 million in sales each year with a standard deviation of 0.9. Trent wants to know if the average sales generated by McDonald's restaurants in Kentucky is different than the worldwide average. He surveys 27 restaurants in Kentucky and finds the following data (in millions of dollars): 4.1, 2.8, 4.4, 4.5, 5.3, 5, 3.7, 2.9, 3.8, 4.8, 3.6, 2.3, 3.7, 2.9, 2.9, 4, 1.1, 5.2, 2.9, 5, 4, 4, 5.9, 3.2, 2.2, 4.3, 3.8 Perform a hypothesis test using a 3% level of significance. Step 1: State the null and alternative hypotheses. Ho: [? v] ? v На: ? ? v (So we will be performing a Select an answer test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are Select an answer v with distribution mean and distribution standard deviation Step 3: Find the p-value of the point estimate. P( ? v ? v = P( ? ♥ ?…
2. Does helping another person affect the helper's life satisfaction? To find out, a researcher randomly sampled 64 people and asked each of them to help one other person that day. At the end of the day, each participant completed a standardized measure of life satisfaction. The mean score for the sample was 51.60. In the general population, the mean score on this measure is 50 and the standard deviation is 6. Test the hypothesis that helping affects life satisfaction (a = .05, two-tailed). You don't have to outline all 5 steps of hypothesis testing, but specify the properties of the comparison distribution, the critical value of the test statistic for rejecting the null hypothesis, the obtained test statistic, and the final decision. What are the lower and upper confidence limits for the 95% confidence interval of the mean life satisfaction of people who have helped someone else that day? Compute the standardized effect size.
Please see the picture below. None of the answers I've tried is coming back right. I just need help with the items in the red boxes.
Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
12. (Two Samples) According to a survey, the mean price of gasoline in the United States was $1.20 per gallon in 1995 and $1.10 per gallon in 1994. (U.S. News & World Report, June 12, 1995). Suppose these means were based on random samples of 100 gasoline stations for 1995 and 120 gasoline stations for 1994. Also, assume that the sample standard deviations were $0.11 for 1995 and $0.10 for 1994. a. Construct a 98% confidence interval for the difference between the mean gasoline prices for 1995 & 1994. b. Test at the 1% significance level if the mean gasoline price was higher in 1995 than in 1994.
Heather recently switched her primary doctor to one specializing in caring for elderly patients. On her new doctor's website, it says that the mean systolic blood pressure among elderly females is 115 millimeters of mercury (mmHg). Heather believes the value is actually higher. She bases her belief on a recently reported study of 13 randomly selected, elderly females. The sample mean systolic blood pressure was 125 mmHg, and the sample standard deviation was 25 mmHg. C Assume that the systolic blood pressures of elderly females are approximately normally distributed. Based on the study, at the 0.05 level of significance, can it be concluded that u, the population mean systolic blood pressure among elderly females, is greater than 115 mmHg? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) state the null hypothesis Ho and the alternative hypothesis H₁. 1 H₂ : 0…

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