Let a displacement vector in the (X,Y) plane be 5.0 m at a 30 degree angle with respect to the x-axis and the force vector 6.0 N at a -45 degree angle with respect to the x-axis. Calculate the work done by the force in moving an object that distance using both methods (trigonometry and vector components). Then calculate the torque acting at that displacement by that force about the origin of the axis system, including the direction of the torque. (Hint: it will be
Let a displacement vector in the (X,Y) plane be 5.0 m at a 30 degree angle with respect to the x-axis and the force vector 6.0 N at a -45 degree angle with respect to the x-axis. Calculate the work done by the force in moving an object that distance using both methods (trigonometry and vector components). Then calculate the torque acting at that displacement by that force about the origin of the axis system, including the direction of the torque. (Hint: it will be
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
100%
![As noted in the text, the scalar product between two vectors A and B can be
calculated using trigonometry as:
Ả B = \Ä||B| cos 0
and the vector product as:
ẢxB = |Ã||B| sin 0 fA
In words, the scalar product between vectors A and B is the product of their
magnitudes and the cosine of the angle between them. The vector product
between vectors A and B is the product of their magnitudes and the sine of the
angle between them. The direction of the resulting vector is perpendicular to
the plane containing the vectors, with the sign of the vector following the right-
hand rule.
The right-hand rule is as follows: begin at vector A and curl the fingers of your
right hand toward vector B. The direction of your thumb is the direction of the
resulting vector. In the traditional sense, the positive direction is above a
horizontal plane and the negative direction is below it.
These quantities can also be calculated if the vectors are expressed in (i,j,k)
notation. If
A = Ayî + Ayƒ + A,k
and
B = B,1 + B,} + B,k
then
÷B = A,B, + A,By + A,B,
and
AxB = \A Ay Az =
(A,B, - A,B2)î + (A,B, – A,Bx)} + (A, B,- Ay Bx)k
|Bx By Bz
53%](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F47b53331-ba4b-4445-9a37-dc5c8bf3b571%2Fff9d8b27-3940-4876-860c-b24427c73e0d%2F87vmfwb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:As noted in the text, the scalar product between two vectors A and B can be
calculated using trigonometry as:
Ả B = \Ä||B| cos 0
and the vector product as:
ẢxB = |Ã||B| sin 0 fA
In words, the scalar product between vectors A and B is the product of their
magnitudes and the cosine of the angle between them. The vector product
between vectors A and B is the product of their magnitudes and the sine of the
angle between them. The direction of the resulting vector is perpendicular to
the plane containing the vectors, with the sign of the vector following the right-
hand rule.
The right-hand rule is as follows: begin at vector A and curl the fingers of your
right hand toward vector B. The direction of your thumb is the direction of the
resulting vector. In the traditional sense, the positive direction is above a
horizontal plane and the negative direction is below it.
These quantities can also be calculated if the vectors are expressed in (i,j,k)
notation. If
A = Ayî + Ayƒ + A,k
and
B = B,1 + B,} + B,k
then
÷B = A,B, + A,By + A,B,
and
AxB = \A Ay Az =
(A,B, - A,B2)î + (A,B, – A,Bx)} + (A, B,- Ay Bx)k
|Bx By Bz
53%
![Both the scalar and vector product have applications in mechanics. The
displacement vector and force vector can be multiplied by both methods,
resulting in different physical quantities.
If multiplied as a scalar product, the resulting quantity is the work done while
pushing or pulling an object from one location to another:
W = d = Fd cos 0
If multiplied as a scalar product, the result is the torque acting on the object,
causing it to begin spinning about an axis, or change its rate of spin:
T= ixF = Fr sin 0 în
When considering work done, the displacement is usually symbolized with a d'
(as in scalar distance) whereas with torque, the displacement is usually
symbolized with an 'r' (as in the radius of a spinning circle).
In this challenge exercise, we are asking you to confirm that both methods of
calculating the scalar and vector products.
Let a displacement vector in the (X,Y) plane be 5.0 m at a 30 degree angle with
respect to the x-axis and the force vector 6.0 N at a -45 degree angle with
respect to the x-axis.
Calculate the work done by the force in moving an object that distance using
both methods (trigonometry and vector components).
Then calculate the torque acting at that displacement by that force about the
origin of the axis system, including the direction of the torque. (Hint: it will be
either the +Z or -Z direction.)
Your solutions should show all the steps necessary to determine the final
answers.
53%](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F47b53331-ba4b-4445-9a37-dc5c8bf3b571%2Fff9d8b27-3940-4876-860c-b24427c73e0d%2Fadcf8y_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Both the scalar and vector product have applications in mechanics. The
displacement vector and force vector can be multiplied by both methods,
resulting in different physical quantities.
If multiplied as a scalar product, the resulting quantity is the work done while
pushing or pulling an object from one location to another:
W = d = Fd cos 0
If multiplied as a scalar product, the result is the torque acting on the object,
causing it to begin spinning about an axis, or change its rate of spin:
T= ixF = Fr sin 0 în
When considering work done, the displacement is usually symbolized with a d'
(as in scalar distance) whereas with torque, the displacement is usually
symbolized with an 'r' (as in the radius of a spinning circle).
In this challenge exercise, we are asking you to confirm that both methods of
calculating the scalar and vector products.
Let a displacement vector in the (X,Y) plane be 5.0 m at a 30 degree angle with
respect to the x-axis and the force vector 6.0 N at a -45 degree angle with
respect to the x-axis.
Calculate the work done by the force in moving an object that distance using
both methods (trigonometry and vector components).
Then calculate the torque acting at that displacement by that force about the
origin of the axis system, including the direction of the torque. (Hint: it will be
either the +Z or -Z direction.)
Your solutions should show all the steps necessary to determine the final
answers.
53%
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