Force F = (-7.0 N)î + (5.0 N) ĵ acts on a particle with position vector7 = (4.0 m)î + (5.0 m) ĵ.(a) What is the torque on the particle about the origin, in unit-vector notation?=N: m(b) What is the angle between the directions of r andTorque is the cross product of a position vector (extending from a chosen point, here the origin, to the particle) and a force vector. Did you take the cross product in unit-vector notation? Do youremember how find the angle between two vectors by taking a dot product in both unit-vector notation and also in magnitude-angle notation? (You can similarly use a cross product to do this.) Do youremember how to find the magnitude of a vector from its components?

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Force F = (-7.0 N)î + (5.0 N) ĵ acts on a particle with position vector 7 = (4.0 m)î + (5.0 m) ĵ. (a) What is the torque on the particle about the origin, in unit-vector notation? N.m (b) What is the angle between the directions of 7 and F? Torque is the cross product of a position vector (extending from a chosen point, here the origin, to the particle) and a force vector. Did you take

Force F = (-7.0 N)î + (5.0 N) ĵ acts on a particle with position vector 7 = (4.0 m)î + (5.0 m) ĵ. (a) What is the torque on the particle about the origin, in unit-vector notation? N.m (b) What is the angle between the directions of 7 and F? Torque is the cross product of a position vector (extending from a chosen point, here the origin, to the particle) and a force vector. Did you take

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