At the presentation ceremony, a championship bowler is presented a 1.80-kg trophy which he holds at arm's length, a distance of 0.655 m from his shoulder joint.(a) Determine the torque the trophy exerts about the shoulder joint when his arm is horizontal. (Enter the magnitude only.)[ ] N · m(b) Determine the torque the trophy exerts about the shoulder joint when his arm is at an angle of 20.0° below the horizontal. (Enter the magnitude only.)[ ] N · m **Problem Statement:**Calculate the torque (in N·m) about the z-axis that is out of the page at the origin in the following figure, given that \( F_1 = 8.0 \, \text{N} \), \( F_2 = 6.0 \, \text{N} \), \( F_3 = 8.0 \, \text{N} \), \( F_4 = 5.7 \, \text{N} \). (Indicate the direction with the sign of your answer.)**Diagram Explanation:**- The diagram shows an x-y coordinate system with four force vectors \( \vec{F_1} \), \( \vec{F_2} \), \( \vec{F_3} \), and \( \vec{F_4} \), each applied at various points and angles relative to vertical and horizontal lines. - Origin is denoted as point O.- Distances from the origin to points of force applications: - A horizontal distance of 2 m is marked along the positive x-axis. - A vertical distance of 2 m is marked along the positive y-axis. - A diagonal distance of 3 m is marked at an angle above the positive x-axis.- Forces and angles: - \( \vec{F_1} \) is directed along the 3 m diagonal line, creating a 90° angle with the line. - \( \vec{F_2} \) acts at a 30° angle above the horizontal (x-axis) at a distance of 2 m on the y-axis. - \( \vec{F_3} \) acts downward along the extended y-axis at a 2 m distance from the origin. - \( \vec{F_4} \) acts at a 20° angle from the vertical line downward and to the right, 2 m from the y-axis.- Each vector is represented by a red arrow and labeled by its respective force magnitude.- The axes and certain force angles are dotted to assist in understanding the force directions and angles. **Calculation Section:**- An empty box is provided at the bottom for the torque value in N·m.

Given , Mass of trophy ? (m) = 1.80 kg Arm's length (L) = 0.655 m

At the presentation ceremony, a championship bowler is presented a 1.80-kg trophy which he holds at arm's length, a distance of 0.655 m from his shoulder joint. (a) Determine the torque the trophy exerts about the shoulder joint when his arm is horizontal. (Enter the magnitude only.) N.m (b) Determine the torque the trophy exerts about the shoulder joint when his arm is at an angle of 20.0° below the horizontal. (Enter the magnitude only.) N. m

At the presentation ceremony, a championship bowler is presented a 1.80-kg trophy which he holds at arm's length, a distance of 0.655 m from his shoulder joint. (a) Determine the torque the trophy exerts about the shoulder joint when his arm is horizontal. (Enter the magnitude only.) N.m (b) Determine the torque the trophy exerts about the shoulder joint when his arm is at an angle of 20.0° below the horizontal. (Enter the magnitude only.) N. m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Torque

Torque is the rotational equivalent of linear force in physics and mechanics. Based on the course of study, it is also known as the moment of force, rotational force, or turning effect.

Question

At the presentation ceremony, a championship bowler is presented a 1.80-kg trophy which he holds at arm's length, a distance of 0.655 m from his shoulder joint.

(a) Determine the torque the trophy exerts about the shoulder joint when his arm is horizontal. (Enter the magnitude only.)

[ ] N · m

(b) Determine the torque the trophy exerts about the shoulder joint when his arm is at an angle of 20.0° below the horizontal. (Enter the magnitude only.)

[ ] N · m

**Problem Statement:**

Calculate the torque (in N·m) about the z-axis that is out of the page at the origin in the following figure, given that \( F_1 = 8.0 \, \text{N} \), \( F_2 = 6.0 \, \text{N} \), \( F_3 = 8.0 \, \text{N} \), \( F_4 = 5.7 \, \text{N} \). (Indicate the direction with the sign of your answer.)

**Diagram Explanation:**

- The diagram shows an x-y coordinate system with four force vectors \( \vec{F_1} \), \( \vec{F_2} \), \( \vec{F_3} \), and \( \vec{F_4} \), each applied at various points and angles relative to vertical and horizontal lines.

- Origin is denoted as point O.

- Distances from the origin to points of force applications:
- A horizontal distance of 2 m is marked along the positive x-axis.
- A vertical distance of 2 m is marked along the positive y-axis.
- A diagonal distance of 3 m is marked at an angle above the positive x-axis.

- Forces and angles:
- \( \vec{F_1} \) is directed along the 3 m diagonal line, creating a 90° angle with the line.
- \( \vec{F_2} \) acts at a 30° angle above the horizontal (x-axis) at a distance of 2 m on the y-axis.
- \( \vec{F_3} \) acts downward along the extended y-axis at a 2 m distance from the origin.
- \( \vec{F_4} \) acts at a 20° angle from the vertical line downward and to the right, 2 m from the y-axis.

- Each vector is represented by a red arrow and labeled by its respective force magnitude.
- The axes and certain force angles are dotted to assist in understanding the force directions and angles.

**Calculation Section:**

- An empty box is provided at the bottom for the torque value in N·m.

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