The wheels of a wagon can be approximated as the combination of a thin outer hoop of radius rh = 0.421 m and mass 5.08 kg, and two thin crossed rods of mass 9.09 kg each. Imagine replacing the wagon wheels with uniform disks that are ta = 6.51 cm thick, made out of a material with a density of 6910 kg/m³. If the new wheel is to have the same moment of inertia about its center as the old wheel about its center, what should the radius of the disk be? ra = 0.365 m

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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**Question 6 of 14**

The wheels of a wagon can be approximated as the combination of a thin outer hoop of radius \( r_h = 0.421 \, \text{m} \) and mass \( 5.08 \, \text{kg} \), and two thin crossed rods of mass \( 9.09 \, \text{kg} \) each. Imagine replacing the wagon wheels with uniform disks that are \( t_d = 6.51 \, \text{cm} \) thick, made out of a material with a density of \( 6910 \, \text{kg/m}^3 \). If the new wheel is to have the same moment of inertia about its center as the old wheel about its center, what should the radius of the disk be?

**Diagram Explanation:**

- The left diagram shows the original wagon wheel with a thin outer hoop of radius \( r_h \) and two crossed rods.
- The right diagram illustrates the new uniform disk with thickness \( t_d \) and radius \( r_d \).

The box to the right states the solution: 
\[ r_d = 0.365 \, \text{m} \]
Transcribed Image Text:**Question 6 of 14** The wheels of a wagon can be approximated as the combination of a thin outer hoop of radius \( r_h = 0.421 \, \text{m} \) and mass \( 5.08 \, \text{kg} \), and two thin crossed rods of mass \( 9.09 \, \text{kg} \) each. Imagine replacing the wagon wheels with uniform disks that are \( t_d = 6.51 \, \text{cm} \) thick, made out of a material with a density of \( 6910 \, \text{kg/m}^3 \). If the new wheel is to have the same moment of inertia about its center as the old wheel about its center, what should the radius of the disk be? **Diagram Explanation:** - The left diagram shows the original wagon wheel with a thin outer hoop of radius \( r_h \) and two crossed rods. - The right diagram illustrates the new uniform disk with thickness \( t_d \) and radius \( r_d \). The box to the right states the solution: \[ r_d = 0.365 \, \text{m} \]
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