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Let a be a real valued constant. Evaluate e-az sec(e¯a«)dx . O - In|sec(e-a*)+ tan(e¬a")|+C In/sec(e)+tan(e¯")| +C - In|sec(e-)+tan(e¯a=)| + C In|sec(e)+tan(e*)| + C

Let a be a real valued constant. Evaluate e-az sec(e¯a«)dx . O - In|sec(e-a*)+ tan(e¬a")|+C In/sec(e)+tan(e¯")| +C - In|sec(e-)+tan(e¯a=)| + C In|sec(e)+tan(e*)| + C

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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D Question 6 Let a be a real valued constant. Evaluate ea sec(e-a")dar . -ax O - In|sec(e-a")+ tan(e-a#)|+C In|sec(e )+tan(e¯a")| + C In|sec(e-a)+tan(e-a")| +C In|sec(e)+tan(e¯*)| +C
Transcribed Image Text:D Question 6 Let a be a real valued constant. Evaluate ea sec(e-a")dar . -ax O - In|sec(e-a")+ tan(e-a#)|+C In|sec(e )+tan(e¯a")| + C In|sec(e-a)+tan(e-a")| +C In|sec(e)+tan(e¯*)| +C
Expert Solution
Step 1

Given: - Let α be a real-valued constant. Then the indefinite integral is,

I=∫e-αxsece-αxdx

To find: - The Solution of the given indefinite integral.

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