Let 8 = {(1, 3), (-2,-2)} and 8' = {(-12, 0), (-4, 4)) be bases for R², and let A = - [83] be the matrix for 7: R² R² relative to 8. (a) Find the transition matrix P from 8' to 8. 6 4 P= 9 4 (b) Use the matrices P and A to find [v] and [7(v)]g, where [v]= [4 -1]. [v]g= Q [7(v)]a = (c) Find A-1 and A' (the matrix for 7 relative to 8'), p-1= - A'= (d) Find [7(v)]g two ways. [7(v)]g = P¹[7(v)]g = [7(v)]g¹ = A'[v]g' =
Let 8 = {(1, 3), (-2,-2)} and 8' = {(-12, 0), (-4, 4)) be bases for R², and let A = - [83] be the matrix for 7: R² R² relative to 8. (a) Find the transition matrix P from 8' to 8. 6 4 P= 9 4 (b) Use the matrices P and A to find [v] and [7(v)]g, where [v]= [4 -1]. [v]g= Q [7(v)]a = (c) Find A-1 and A' (the matrix for 7 relative to 8'), p-1= - A'= (d) Find [7(v)]g two ways. [7(v)]g = P¹[7(v)]g = [7(v)]g¹ = A'[v]g' =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![Let 8 = {(1, 3), (-2,-2)} and 8' = {(-12, 0), (-4, 4)) be bases for R², and let
A =
- [83]
be the matrix for 7: R² R² relative to 8.
(a) Find the transition matrix P from 8' to 8.
6
4
P=
9
4
(b) Use the matrices P and A to find [v] and [7(v)]g, where
[v]= [4 -1].
[v]g=
Q
[7(v)]a =
(c) Find A-1 and A' (the matrix for 7 relative to 8'),
p-1=
-
A'=
(d) Find [7(v)]g two ways.
[7(v)]g = P¹[7(v)]g =
[7(v)]g¹ = A'[v]g' =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd496c25d-6621-40aa-914c-10320ef32b36%2F64fcbdee-891d-48f1-ae43-fe6d485de288%2Fzyz1drm_processed.png&w=3840&q=75)
Transcribed Image Text:Let 8 = {(1, 3), (-2,-2)} and 8' = {(-12, 0), (-4, 4)) be bases for R², and let
A =
- [83]
be the matrix for 7: R² R² relative to 8.
(a) Find the transition matrix P from 8' to 8.
6
4
P=
9
4
(b) Use the matrices P and A to find [v] and [7(v)]g, where
[v]= [4 -1].
[v]g=
Q
[7(v)]a =
(c) Find A-1 and A' (the matrix for 7 relative to 8'),
p-1=
-
A'=
(d) Find [7(v)]g two ways.
[7(v)]g = P¹[7(v)]g =
[7(v)]g¹ = A'[v]g' =
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