Let be A, B, C,x. 5x5 matrixes such that A, B and C can be inverted such that AXB" – 151, = c-1 According to that, an equivalent equation to the previous shown is. O a) X = (C-1+1515)A¯'(B")-1 Ob) X = A-(C-1 + 151;)(B")-1 Oc) X = (B")-'(C-+1515)A¬! O d) X = A-(B")"(C-1+15I5)

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