Le e-x² dx = √√π, (23.5) | u(x, t) | ≤ L 4πt M e-(x-y)²/4t d = √ √ e-(2-1)/ 2√/1/2 dy. 24.4 Problem. Substitute s = (x − y)/2√t in the integral on the right and use (23.5) - to derive a bound for u that is independent of t.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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Le
e-x² dx = √√π,
(23.5)
| u(x, t) | ≤ L
4πt
M
e-(x-y)²/4t d = √ √ e-(2-1)/ 2√/1/2
dy.
24.4 Problem. Substitute s = (x − y)/2√t in the integral on the right and use (23.5)
-
to derive a bound for u that is independent of t.
Transcribed Image Text:Le e-x² dx = √√π, (23.5) | u(x, t) | ≤ L 4πt M e-(x-y)²/4t d = √ √ e-(2-1)/ 2√/1/2 dy. 24.4 Problem. Substitute s = (x − y)/2√t in the integral on the right and use (23.5) - to derive a bound for u that is independent of t.
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