-6x 2 For the linear differential equation y' + 6xy = x³ e² the integrating factor is: r(x) = ☐ help (formulas). After multiplying both sides by the integrating factor and "unapplying" the product rule we get the new differential equation: d dx ·[0] = = ☐ help (formulas) Integrating both sides we get the algebraic equation ☐ = ☐ +C help (formulas) Solving for y, the general solution to the differential equation is У ☐ help (formulas) Note: Use C as the constant. Book: Section 1.4 of Notes on Diffy Qs
-6x 2 For the linear differential equation y' + 6xy = x³ e² the integrating factor is: r(x) = ☐ help (formulas). After multiplying both sides by the integrating factor and "unapplying" the product rule we get the new differential equation: d dx ·[0] = = ☐ help (formulas) Integrating both sides we get the algebraic equation ☐ = ☐ +C help (formulas) Solving for y, the general solution to the differential equation is У ☐ help (formulas) Note: Use C as the constant. Book: Section 1.4 of Notes on Diffy Qs
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Answer the blank boxes
![-6x
2
For the linear differential equation y' + 6xy = x³ e² the integrating factor is:
r(x)
=
☐ help (formulas).
After multiplying both sides by the integrating factor and "unapplying" the product rule we get the new differential
equation:
d
dx
·[0] =
=
☐ help (formulas)
Integrating both sides we get the algebraic equation
☐ = ☐ +C
help (formulas)
Solving for y, the general solution to the differential equation is
У
☐ help (formulas)
Note: Use C as the constant.
Book: Section 1.4 of Notes on Diffy Qs](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff9a2dab3-72cf-4044-ac86-05d83f420c4a%2Fa64e4c34-9761-44d3-99a3-f9a7fe31a172%2Fpnvfxtm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:-6x
2
For the linear differential equation y' + 6xy = x³ e² the integrating factor is:
r(x)
=
☐ help (formulas).
After multiplying both sides by the integrating factor and "unapplying" the product rule we get the new differential
equation:
d
dx
·[0] =
=
☐ help (formulas)
Integrating both sides we get the algebraic equation
☐ = ☐ +C
help (formulas)
Solving for y, the general solution to the differential equation is
У
☐ help (formulas)
Note: Use C as the constant.
Book: Section 1.4 of Notes on Diffy Qs
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