@ Find the nth term of the series. 1 + 4 × ² + 1 8 X² + 3/16 x + 11 960 X+ prove that the Series 4 - 4 x² + 48 × + · 960 b X + is solution of integral equation 4(x) = 1 + $ √xudt
@ Find the nth term of the series. 1 + 4 × ² + 1 8 X² + 3/16 x + 11 960 X+ prove that the Series 4 - 4 x² + 48 × + · 960 b X + is solution of integral equation 4(x) = 1 + $ √xudt
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![@
Find the nth term of the
series.
1 + 4 × ² + 1 8 X² + 3/16 x + 11
960
X+
prove that
the Series
4
- 4 x² + 48 × + ·
960
b
X +
is solution of integral
equation
4(x) = 1 + $ √xudt](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc787d915-c07e-4d96-9be2-525f136913ba%2Fc33d44dc-c378-437f-9d4c-4fe58907117f%2Fewac6dv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:@
Find the nth term of the
series.
1 + 4 × ² + 1 8 X² + 3/16 x + 11
960
X+
prove that
the Series
4
- 4 x² + 48 × + ·
960
b
X +
is solution of integral
equation
4(x) = 1 + $ √xudt
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