Last Digit 4 30 Frequency 35 24 25 27 35 37 27 36 24
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A: Outcomes Frequency O1271A1123B328AB158Total2880
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Exercises 1–5 refer to the sample data in the following table, which summarizes the last digits of the heights (cm) of 300 randomly selected subjects (from Data Set 1 “Body Data” in Appendix B). Assume that we want to use a 0.05 significance level to test the claim that the data are from a population having the property that the last digits are all equally likely.
Is the hypothesis test left-tailed, right-tailed, or two-tailed?
The chi-square test statistic is based on the difference between the observed frequency and the expected frequency. Also, it is assumed that the row variables and the column variables are independent.
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- Travelers who have no intention of showing up often fail to cancel their hotel reservations in a timely manner. These travelers are known, in the parlance of the hospitality trade, as “no-shows”. To protect against no-shows and late cancellations, hotels invariably overbook rooms. A recent study examined the problems of over-booking rooms in the hotel industry. The following data, extracted from the study represent the daily numbers of late cancellations and no-shows for a random sample of 10 days at a hotel: 18, 16, 16, 16, 14, 18, 16, 18, 14, 19. c) Count the number of measurements that actually fall within the interval(x¯−2s, x¯+2s){ and express the interval count as a percentage of total number of measurementsIf you are running a hypothesis test and increase your sample size, what will happen to your Type I and Type Il error? a. Type I will increase, Type Il will increase b. Type I will decrease, Type Il will decrease O c. Type I will increase, Type II will decrease O d. Type l will decrease, Type II will increaseIn the US, 46.2% of all people have type O blood, 39.1% have type A blood, 10.4% have type B blood and 4.3% have type AB blood. A researcher wants to see if the distribution of blood type is different for millionaires. The table below shows the results of a random sample of 3116 millionaires. What can be concluded at the a = 0.01 significance level? a. Complete the table by filling in the expected frequencies. Round to the nearest vwhole number: Frequencies of Blood Type Outcome Frequency Expected Frequency 1434 A 1224 В 310 АВ 148 b. What is the correct statistical test to use? Select an answer V c. What are the null and alternative hypotheses? Ho: Blood type and income are independent. O The distribution of blood type for millionaires is not the same as it is for Americans in general. O The distribution of blood type for millionaires is the same as it is for Americans in general. O Blood type and income are dependent.
- In studying the responses to questions on a multiple-choice test, the following sample data are obtained. At the a 0.05 significance level, test the claim that the responses occur with the same frequency. Ho: The responses to the questions occur with the same frequency. H₁: The responses to the questions do not occur with the same frequency. Observed Response Frequency Expected Frequency (0-E)2 E A 6 16.2 8 B 10 16.2 C 24 16.2 D 18 16.2 8 E 23 16.2 a. What is the X2 test-statistic for this data? Round to four decimal places. x²= b. What is the p-value? Round to four decimal places. p-value= c. What would be the conclusion of this hypothesis test? O Fail to reject the hull hypothesis. Reject the null hypothesis. d. What is the final conclusion? O There is sufficient evidence to conclude the test question responses occur with the same frequency. There is sufficient evidence to conclude the test question responses do not occur with the same frequency. O There is not sufficient evidence to…Travelers who have no intention of showing up often fail to cancel their hotel reservations in a timely manner. These travelers are known, in the parlance of the hospitality trade, as “no-shows”. To protect against no-shows and late cancellations, hotels invariably overbook rooms. A recent study examined the problems of over-booking rooms in the hotel industry. The following data, extracted from the study represent the daily numbers of late cancellations and no-shows for a random sample of 10 days at a hotel: 18, 16, 16, 16, 14, 18, 16, 18, 14, 19. a) Compute s, the sample s.d. for the data setA set of data was published in the fall 2019 Phi Kappa Phi Forum regarding the performance of Major League Baseball (MLB) umpires in calling balls and strikes. The article is based on data collected by MLB over eleven seasons (2008-2018). This study shows that it is common for umpires to make incorrect calls more than 20% of the time. An average game has about 300 pitches where the umpire has to make a decision. Assume that we take a random sample of 300 of the 4 million ball/strike calls in the database. Our analysis of a new sample yielded a Z test statistic of 2.17 for this one-sided test to the right. The p-value is = .015. Make a decision on this hypothesis test using a 5% level of significance and state the reason for your decision. O Reject the null hypothesis since the p-value is .01
- This data set contains the achievement test (English as a Second Language) results and some background data collected during experimental trial of a new ESL program. The study was one year in duration. Students were allocated to the experimental ESL program class and a regular program control class on a random basis. Vocabulary and grammar tests were administered to the students in both groups at the beginning and the end of the school year. Variables The dataset includes 24 cases and 7 variables: Student ID Group (1 - experimental, 2 - control, 9 - missing) Gender (1 - male, 2 - female, 9 - missing) Pre-test vocabulary scores (scores range from 0 - 25, 99 - missing) Pre-test grammar scores (scores range from 0 - 25, 99 - missing) Post-test vocabulary scores (scores range from 0 - 25, 99 - missing) Post-test grammar scores (scores range from 0 - 25, 99 - missing) (a) develop a research question that can be addressed with independent-samples t test (b) state the null and alternative…When three groups were compared using the one-way Analysis of Variance (ANOVA), the result turned out to be significant, that is, the null hypothesis was rejected. What will be the appropriate interpretation of this result?A. All three groups significantly differ in means.B. Exactly two of the three groups significantly differ.C. At least two of the three groups significantly differ in means.D. All three groups have the same effect on the dependent variable.1. Write a complete paragraph in APA format describing the research question and your results. Question: A social psychologist records the number of outbursts among students at two schools. Assuming the same number of students were observed at each school, what is the sample size at each school, the decision to retain or reject the null hypothesis) and the effect size for this study based on the following statement? The number of outbursts among students at the small school (M=3) was significantly less than the number recorded at the large school (M = 5) f(38) =4.19, p < .05(d = 0.25 ). Results: sample size = 20 for each school For a two tailed test and df = 38, at 0.05 significance level, t = 2.023 (from t distribution table) Here, the critical value is less than t obtained (t2.023 < 4.19) Hence, we reject the null hypothesis at a 5% significance level Given that d = 0.25 => effect size is medium (since 0.2<d<0.8 for medium) Therefore, the study showed a medium…
- If sample data is such that for a one-tailed test of ? you can reject H0 at the 1% level of significance, can you always reject H0 for a two-tailed test at the same level of significance? Explain your answer? A. Yes. If H0 for a one-tailed test is rejected at the 1% level of significance, it will always be rejected for a two-tailed test at the same level of significance. B. No. If H0 for a one-tailed test is rejected at the 1% level of significance, it will never be rejected for a two-tailed test at the same level of significance. C. Yes. The P-value for the two-tailed test could be greater than 0.01. D. No. The P-value for the two-tailed test could be greater than 0.01.Suppose we wanted to compare the average BMI of a sample of Charleston County residents to the average BMI of US adults (u-26.5). Use the data in the table below to conduct the appropriate hypothesis test to see if the average BMI of our sample of Charleston County residents is significantly different than the US adult average. CHS Sample BMI 25.3 27.5 24.2 27.5 28.6 28.6 24.2 22 23.1 29.7 20.9 25.3 26.4 22 29.7 28.6 26.4 24.2 20.9 25.3 What is the value for the test statistic? (round to two decimal places)In a large clinical trial, 395,241 children were randomly assigned to two groups. The treatment group consisted of 197,457 children given a vaccine for a certain disease, and 38 of those children developed the disease. The other 197,784 children were given a placebo, and 143 of those children developed the disease. Consider the vaccine treatment group to be the first sample. Complete parts (a) through (d) below. a. Assume that a 0.05 significance level will be used to test the claim that p₁SEE MORE QUESTIONS