Sample mean Error Sample variance Plant 1 Plant 2 Plant 3 Atlanta Dallas Seattle 85 10 M₂ M₂ M₂ M₂ 76 75 " 72 90 80 46.8 71 76 15 73 68 89 75 60 65 62 45 68 76 Sample standard 6.84 deviation t up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum Degrees Mean of Variation of Squares of Freedom Square Treatments 71 54.0 35.2 OM: Not all the population means are equal. M₂M₂H₂M₂ 7.35 5.93 Total at for any significant difference in the mean examination score for the three plants. Use a -0.05. ate the null and alternative hypotheses. Mg! H₂H₂ My H: Not all the population means are equal. Mg: At least two of the population means are equal. M₁: At least two of the population means are different. F p-value
Sample mean Error Sample variance Plant 1 Plant 2 Plant 3 Atlanta Dallas Seattle 85 10 M₂ M₂ M₂ M₂ 76 75 " 72 90 80 46.8 71 76 15 73 68 89 75 60 65 62 45 68 76 Sample standard 6.84 deviation t up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum Degrees Mean of Variation of Squares of Freedom Square Treatments 71 54.0 35.2 OM: Not all the population means are equal. M₂M₂H₂M₂ 7.35 5.93 Total at for any significant difference in the mean examination score for the three plants. Use a -0.05. ate the null and alternative hypotheses. Mg! H₂H₂ My H: Not all the population means are equal. Mg: At least two of the population means are equal. M₁: At least two of the population means are different. F p-value
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question

Transcribed Image Text:A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following
table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants.
Source
of Variation
Treatments
Error
Sample
mean
Total
Plant 1 Plant 2 Plant 3
Atlanta Dallas
Seattle
85
76
82
75
о но: М1 =H2=Из
на: M1 #M2 + M3
72
90
Sample 46.8
variance
Sample
standard 6.84
deviation
80
71
76
73
73
68
89
75
54.0
7.35
Sum
Degrees
of Squares of Freedom
60
65
о но: М1 =H2= из
H₂: Not all the population means are equal.
62
Set up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)
68
76
71
67
35.2
5.93
Mean
Square
Test for any significant difference in the mean examination score for the three plants. Use α = 0.05.
State the null and alternative hypotheses.
о но: H1 #M2 # Из
Ha: H1 = M2 = M3
O Ho: At least two of the population means are equal.
H₂: At least two of the population means are different.
F
O Ho: Not all the population means are equal.
на: М1 = M2 = M3
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
p-value
State your conclusion.
Reject Ho. There is not sufficient evidence to conclude that the means for the three plants are not equal.
Do not reject Ho. There is sufficient evidence to conclude that the means for the three plants are not equal.
O Do not reject Ho. There is not sufficient evidence to conclude that the means for the three plants are not equal.
O Reject Ho. There is sufficient evidence to conclude that the means for the three plants are not equal.
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