Largest Member 2 Area = 34 P y P← -X Area = Member 4 A 4/2 P P ·x Member 1 Area = A y P P -X Member 3 Area = 24 P Smallest

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Four axially loaded members are shown below. All members have the same value for E (Young’s modulus) and for ν (Poisson’s ratio).

V
Largest
Member 2
Area = 34
P
y
P◄
O The correct ranking cannot be determined.
a
a
Area =
Member 4
2
y
·x
Member 1
Area = A
P
y
P.
-X
Member 3
Area = 24
Smallest
Transcribed Image Text:V Largest Member 2 Area = 34 P y P◄ O The correct ranking cannot be determined. a a Area = Member 4 2 y ·x Member 1 Area = A P y P. -X Member 3 Area = 24 Smallest
Expert Solution
Step 1: Given:

There are four cases in which all the components have different cross sectional areas and load.

But have same youngs modulus and poissions ratio.

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